回答編集履歴
3
answer
CHANGED
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@@ -1,54 +1,49 @@
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```
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#include <stdio.h>
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3
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4
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typedef struct { int n, d; } frac;
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typedef frac (*Op)(frac, frac);
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frac add(frac a, frac b) { return (frac){ a.n*b.d + b.n*a.d, a.d*b.d }; }
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frac sub(frac a, frac b) { return (frac){ a.n*b.d - b.n*a.d, a.d*b.d }; }
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frac mul(frac a, frac b) { return (frac){ a.n*b.n, a.d*b.d }; }
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10
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frac div(frac a, frac b) { return (frac){ a.n*b.d, a.d*b.n }; }
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Op o[] = { add, sub, mul, div };
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char* op_str[] = { "＋", "－", "×", "÷" };
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int is10(frac x) { return x.n == x.d * 10; }
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int main()
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{
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char str[256];
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printf("4桁の数字を入力してください。\n");
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scanf_s("%s", str,256);
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printf("入力値は「%s」です。\n", str);
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frac a = { str[0] - '0', 1 };
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frac b = { str[1] - '0', 1 };
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frac c = { str[2] - '0', 1 };
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frac d = { str[3] - '0', 1 };
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for (int i = 0; i < 4; i++)
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for (int j = 0; j < 4; j++)
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for (int k = 0; k < 4; k++) {
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// (a+b)+(c+d)
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if (is10(o[i](a, o[j](b,
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printf("%c %s
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str[1], op_str[j], str[2], op_str[k], str[3]);
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//
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49
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printf("%c %s {(%c %s %c) %s %c}\n", str[0], op_str[i],
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str[1], op_str[j], str[2], op_str[k], str[3]);
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}
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}
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54
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```
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1
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```c
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2
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#include <stdio.h>
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3
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4
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typedef struct { int n, d; } frac;
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5
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typedef frac (*Op)(frac, frac);
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6
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7
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frac add(frac a, frac b) { return (frac){ a.n*b.d + b.n*a.d, a.d*b.d }; }
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8
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frac sub(frac a, frac b) { return (frac){ a.n*b.d - b.n*a.d, a.d*b.d }; }
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9
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frac mul(frac a, frac b) { return (frac){ a.n*b.n, a.d*b.d }; }
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10
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frac div(frac a, frac b) { return (frac){ a.n*b.d, a.d*b.n }; }
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11
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12
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Op o[] = { add, sub, mul, div };
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13
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char* op_str[] = { "＋", "－", "×", "÷" };
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14
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15
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int is10(frac x) { return x.n == x.d * 10; }
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16
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17
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int main()
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{
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char str[256];
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printf("4桁の数字を入力してください。\n");
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scanf("%255s", str); // scanf_s("%s", str, 256);
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printf("入力値は「%s」です。\n", str);
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frac a = { str[0] - '0', 1 };
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frac b = { str[1] - '0', 1 };
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frac c = { str[2] - '0', 1 };
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frac d = { str[3] - '0', 1 };
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28
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29
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for (int i = 0; i < 4; i++)
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for (int j = 0; j < 4; j++)
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31
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for (int k = 0; k < 4; k++) {
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32
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if (is10(o[j](o[i](a, b), o[k](c, d)))) // (a+b)+(c+d)
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33
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printf("(%c %s %c) %s (%c %s %c)\n", str[0], op_str[i],
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str[1], op_str[j], str[2], op_str[k], str[3]);
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35
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if (is10(o[k](o[j](o[i](a, b), c),d))) // {(a+b)+c}+d
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printf("{(%c %s %c) %s %c} %s %c\n", str[0], op_str[i],
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str[1], op_str[j], str[2], op_str[k], str[3]);
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38
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if (is10(o[i](a, o[j](b, o[k](c, d))))) // a+{b+(c+d)}
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printf("%c %s {%c %s (%c %s %c)}\n", str[0], op_str[i],
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str[1], op_str[j], str[2], op_str[k], str[3]);
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41
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if (is10(o[k](o[i](a, o[j](b, c)), d))) // {a+(b+c)}+d
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42
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printf("{%c %s (%c %s %c)} %s %c\n", str[0], op_str[i],
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43
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str[1], op_str[j], str[2], op_str[k], str[3]);
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44
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if (is10(o[i](a, o[k](o[j](b, c), d)))) // a+{(b+c)+d}
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45
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printf("%c %s {(%c %s %c) %s %c}\n", str[0], op_str[i],
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46
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str[1], op_str[j], str[2], op_str[k], str[3]);
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47
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}
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48
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}
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49
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```
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2
コードの修正
answer
CHANGED
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@@ -28,7 +28,7 @@
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28
28
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29
29
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for (int i = 0; i < 4; i++)
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30
30
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for (int j = 0; j < 4; j++)
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31
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-
for (int k = 0; k < 4; k++)
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31
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for (int k = 0; k < 4; k++) {
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32
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// (a+b)+(c+d)
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33
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if (is10(o[j](o[i](a, b), o[k](c, d))))
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34
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printf("(%c %s %c) %s (%c %s %c)\n", str[0], op_str[i],
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@@ -49,5 +49,6 @@
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49
49
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if (is10(o[i](a, o[k](o[j](b, c), d))))
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50
50
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printf("%c %s {(%c %s %c) %s %c}\n", str[0], op_str[i],
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51
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str[1], op_str[j], str[2], op_str[k], str[3]);
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52
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}
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52
53
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}
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53
54
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```
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1
コードの修正
answer
CHANGED
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@@ -44,7 +44,7 @@
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44
44
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// {a+(b+c)}+d
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45
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if (is10(o[k](o[i](a, o[j](b, c)), d)))
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46
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printf("{%c %s (%c %s %c)} %s %c\n", str[0], op_str[i],
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47
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str[1], op_str[j], str[
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str[1], op_str[j], str[2], op_str[k], str[3]);
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48
48
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// a+{(b+c)+d}
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49
49
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if (is10(o[i](a, o[k](o[j](b, c), d))))
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50
50
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printf("%c %s {(%c %s %c) %s %c}\n", str[0], op_str[i],
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