回答編集履歴
2
修正
test
CHANGED
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@@ -1,3 +1,131 @@
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もしかしたらもっと速い実装あるかもしれませんが…
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3
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生成規則をもとに素直に実装していけばよいです。
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5
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以下のように累積的に求めていけばよいです。
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```Python
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9
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n = 3
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10
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ret_list = [[0]]
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for i in range(1,n):
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new_list = []
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for one in ret_list:
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# ひとつ手前の要素の値に-1,+0,+1した要素を追加
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new_list.append( one + [one[i-1]-1])
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new_list.append( one + [one[i-1]])
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new_list.append( one + [one[i-1]+1])
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ret_list = new_list
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print(*ret_list, sep='\n')
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"""
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35
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n=2
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36
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[0, -1]
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39
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[0, 0]
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40
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41
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[0, 1]
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42
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43
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n=3
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44
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45
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[0, -1, -2]
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46
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[0, -1, -1]
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48
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[0, -1, 0]
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51
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[0, 0, -1]
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52
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53
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[0, 0, 0]
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54
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55
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[0, 0, 1]
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[0, 1, 0]
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[0, 1, 1]
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[0, 1, 2]
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63
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n=4
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64
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[0, -1, -2, -3]
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[0, -1, -2, -2]
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69
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[0, -1, -2, -1]
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[0, -1, -1, -2]
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[0, -1, -1, -1]
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[0, -1, -1, 0]
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[0, -1, 0, -1]
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[0, -1, 0, 0]
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80
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81
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[0, -1, 0, 1]
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[0, 0, -1, -2]
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85
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[0, 0, -1, -1]
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[0, 0, -1, 0]
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[0, 0, 0, -1]
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[0, 0, 0, 0]
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[0, 0, 0, 1]
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[0, 0, 1, 0]
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[0, 0, 1, 1]
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[0, 0, 1, 2]
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[0, 1, 0, -1]
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[0, 1, 0, 0]
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[0, 1, 0, 1]
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[0, 1, 1, 0]
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[0, 1, 1, 1]
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[0, 1, 1, 2]
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[0, 1, 2, 1]
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115
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[0, 1, 2, 2]
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[0, 1, 2, 3]
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118
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119
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"""
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120
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121
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```
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122
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123
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124
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125
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# 以前の回答
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126
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127
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128
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1
129
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`i`の場合の取りえる数値は`-i`～`+i`と表せるので以下でよいかと思います。
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2
130
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3
131
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```Python
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1
修正
test
CHANGED
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@@ -23,3 +23,5 @@
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23
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[-4, -3, -2, -1, 0, 1, 2, 3, 4]
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"""
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```
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