回答編集履歴
2
修正
answer
CHANGED
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@@ -1,5 +1,46 @@
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1
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```VBA
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2
2
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Sub sample()
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3
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4
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Dim score(1 To 5, 1 To 3)
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5
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Dim avgAry(1 To 5)
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6
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Dim sdAry(1 To 5)
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7
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Dim minAry(1 To 5)
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8
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Dim maxAry(1 To 5)
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9
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10
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Dim i, j
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For i = 1 To 5
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12
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For j = 1 To 3
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score(i, j) = Cells(i + 1, j + 1).Value
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Next j, i
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16
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For i = 1 To 5
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Dim sm, mn, mx, sd
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sm = 0
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mn = 100
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mx = 0
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sd = 0
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For j = 1 To 3
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sm = sm + score(i, j)
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If score(i, j) < mn Then mn = score(i, j)
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If score(i, j) > mx Then mx = score(i, j)
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Next
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avgAry(i) = sm / 3
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minAry(i) = mn
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maxAry(i) = mx
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For j = 1 To 3
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sd = sd + (score(i, j) - avgAry(i)) ^ 2
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Next
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sdAry(i) = Sqr(sd / 3)
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Next
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End Sub
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```
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```VBA
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43
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Sub sample2()
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3
44
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Dim arr As Variant
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45
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arr = Range("B2:D6").Value
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5
46
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@@ -12,6 +53,7 @@
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Dim i
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For i = 1 To 5
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avgAry(i) = .Average(.Index(arr, i, 0))
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56
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sdAry(i) = .StDev_P(.Index(arr, i, 0))
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minAry(i) = .Min(.Index(arr, i, 0))
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maxAry(i) = .Max(.Index(arr, i, 0))
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Next
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1
追記
answer
CHANGED
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@@ -2,10 +2,19 @@
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2
2
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Sub sample()
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3
3
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Dim arr As Variant
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4
4
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arr = Range("B2:D6").Value
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5
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6
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Dim avgAry(1 To 5)
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7
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Dim sdAry(1 To 5)
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8
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Dim minAry(1 To 5)
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9
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Dim maxAry(1 To 5)
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10
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11
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With WorksheetFunction
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5
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-
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12
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Dim i
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6
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-
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13
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For i = 1 To 5
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7
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-
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avgAry(i) = .Average(.Index(arr, i, 0))
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8
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-
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minAry(i) = .Min(.Index(arr, i, 0))
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maxAry(i) = .Max(.Index(arr, i, 0))
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9
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-
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Next
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End With
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End Sub
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```
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