回答編集履歴
2
追加に対する回答
test
CHANGED
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@@ -41,3 +41,63 @@
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41
41
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(5, 0.5)
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42
42
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43
43
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```
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44
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+
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45
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+
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46
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+
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47
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+
やりたいことが完全には分かりませんが、以下を参考にして考えてみてください。
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48
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+
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49
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+
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50
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51
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```python
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52
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53
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>>> print(df)
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54
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55
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hoge fuga value1 value2 value3 value4
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56
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57
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0 0.1 a 150 0 0 0
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58
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+
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59
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1 0.2 b 130 0 0 0
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60
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+
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61
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2 0.3 c 120 0 0 0
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62
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63
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3 0.4 d 90 0 0 0
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64
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65
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4 0.5 e 70 0 0 0
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66
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67
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5 0.1 a 300 0 0 0
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68
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69
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>>> print(datas)
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70
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71
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{1: 0.1, 2: 0.2, 5: 0.5}
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72
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73
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>>> for key, value in datas.items():
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74
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75
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... if (df['hoge'] == value).any():
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76
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77
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... print(f"key = {key}")
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78
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79
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... print(df[df['hoge'] == value]['value1'])
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80
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81
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...
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82
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83
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key = 1
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84
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85
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0 150
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86
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87
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5 300
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88
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89
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Name: value1, dtype: int64
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90
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91
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key = 2
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92
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93
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1 130
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94
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95
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Name: value1, dtype: int64
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96
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97
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key = 5
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98
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99
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4 70
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100
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101
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Name: value1, dtype: int64
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102
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+
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103
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```
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1
説明追加
test
CHANGED
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@@ -23,3 +23,21 @@
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23
23
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```
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24
24
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25
25
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この構文で返ってくるのは、keyとvalueのタプルではなく、keyだけだからです。
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26
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+
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27
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keyとvalueのタプルが必要なら、以下のようにしてください。
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28
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29
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```python
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30
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31
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>>> for x in datas.items():
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32
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33
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... print(x)
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34
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35
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...
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36
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37
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(1, 0.1)
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38
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39
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(2, 0.2)
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40
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+
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41
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(5, 0.5)
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42
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+
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43
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+
```
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