回答編集履歴
3
追記
answer
CHANGED
@@ -54,4 +54,96 @@
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ret.sort(key=lambda v:v[0]) # 結果を席番号順に
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print(ret)# [(1, 4), (2, 3), (3, 2), (4, 1), (5, 5), (6, 6)]
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```
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#追記2
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処理を見直しました。
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これならおそらくうまく割り振られると思います。
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```Python
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import random
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seat_1 = [2,3,4,5,6,7,8,12,13,15,19,22,30,31]
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seat_2 = [2,3,4,5,6,7,8,13,15,16,19,20,22,25,26,30,31,36]
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seat_3 = [2,4,6,7,8,14,15,16,20,25,26,30,33,36,37]
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seat_4 = [1,2,4,6,7,8,14,15,16,17,20,23,25,26,28,30,33,36,37]
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seat_5 = [1,2,4,6,7,8,14,16,17,20,23,25,26,28,30,33,36,37]
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seat_6 = [29]
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seat_7 = [2,3,6,7,8,10,15,16,19,22,25,30,31,36]
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seat_8 = [2,6,7,8,10,14,15,16,25,30,33,36,37]
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seat_9 = [1,2,6,7,8,10,14,15,16,17,23,25,28,30,33,36,37]
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seat_10 = [1,2,6,7,8,14,16,17,23,25,28,30,32,33,36,37]
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seat_11 = [1,2,4,6,7,8,14,16,17,18,23,28,30,32,33,34,37]
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seat_12 = [5,6,7,8,12,13,22,30,31]
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seat_13 = [5,6,7,8,13,22,30,31]
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seat_14 = [6,7,8,10,16,22,30,31]
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seat_15 = [6,7,8,10,14,16,21,30,33,37]
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seat_16 = [1,6,7,8,10,14,16,17,21,23,28,30,33,37]
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seat_17 = [1,6,7,8,14,16,17,21,23,28,30,33,37]
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seat_18 = [1,4,6,7,8,14,16,17,18,23,28,30,32,33,34,37]
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seat_19 = [5,6,7,8,12,13,22,30]
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seat_20 = [5,6,7,8,13,22,24,30]
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seat_21 = [6,7,8,10,16,22,24,30]
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seat_22 = [6,7,8,10,14,16,21,30,33,37]
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seat_23 = [1,6,7,8,10,14,16,17,21,23,28,30,33,37]
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seat_24 = [1,6,7,8,14,16,17,21,23,28,30,33,37]
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seat_25 = [1,4,6,7,8,14,16,17,18,23,28,30,32,33,34,37]
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seat_26 = [5,6,7,8,12,13,22,30]
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seat_27 = [5,6,7,8,13,22,24,30]
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seat_28 = [6,7,8,10,16,22,24,30]
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seat_29 = [6,7,8,10,14,16,24,30,33,37]
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seat_30 = [1,6,7,8,10,14,16,17,23,28,30,33,37]
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seat_31 = [1,6,7,8,14,16,17,23,28,30,33,37]
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seat_32 = [1,4,6,7,8,14,16,17,18,23,28,30,32,33,34,37]
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seat_33 = [4,5,6,7,8,13,22,24,27,30]
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seat_34 = [27]
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seat_35 = [11]
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seat_36 = [9]
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seat_37 = [35]
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seats = [seat_1,seat_2,seat_3,seat_4,seat_5,
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seat_6,seat_7,seat_8,seat_9,seat_10,
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seat_11,seat_12,seat_13,seat_14,seat_15,
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seat_16,seat_17,seat_18,seat_19,seat_20,
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seat_21,seat_22,seat_23,seat_24,seat_25,
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seat_26,seat_27,seat_28,seat_29,seat_30,
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seat_31,seat_32,seat_33,seat_34,seat_35,
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seat_36,seat_37]
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# (席番号, 候補リスト)に整形
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seats = [(i+1,v) for i,v in enumerate(seats)]
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ret = []
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while seats:
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for i, seat in enumerate(seats):
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# 候補がいる席に対して抽選
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# (最初は人気がなくて候補がいない席もあることを考慮)
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if len(seat[1]) >= 1:
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seat = seats.pop(i) # popによって今から抽選する席番号は取り除かれる
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# 抽選して結果を保存
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win = random.choice(seat[1]) # 当選した人番号
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ret.append((seat[0], win)) # (席番号, 人番号)
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# 各席から当選した人を取り除く
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seats = [ (s[0], [p for p in s[1] if p != win]) for s in seats]
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# 落選した人で、他にどの席も希望していない人は
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# あぶれるので有無を言わせず(ランダムに)別の席の抽選に振り分ける
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loses = [v for v in seat[1] if v != win]
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for lose in loses:
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is_exist = False
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for seat in seats:
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if lose in seat[1]:
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is_exist = True
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break
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if not is_exist:
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seat = random.choice(seats)
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seat[1].append(lose)
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break
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assert(len(ret) == len(set([v[0] for v in ret]))) # すべての席に割り当てられた
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assert(len(ret) == len(set([v[1] for v in ret]))) # すべての人が割り当てられた
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ret.sort(key=lambda v:v[0]) # 結果を席番号順に
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print(ret)
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```
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2
修正
answer
CHANGED
@@ -13,7 +13,7 @@
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```
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# 追記
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いや、
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いや、以下ではだめですね。
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席1に1と3番、席2と席3に1と2番の人が希望した場合、席1に1番の人が座ると破綻しますね。
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~~ちなみに、以下のような抽選方法だと席の数のループだけで結果が得られます。
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1
追記
answer
CHANGED
@@ -12,8 +12,13 @@
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#[1, 5, 2, 3, 4, 6]
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```
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# 追記
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いや、これではだめですね。
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席1に1と3番、席2と席3に1と2番の人が希望した場合、席1に1番の人が座ると破綻しますね。
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ちなみに、以下のような抽選方法だと席の数のループだけで結果が得られます。
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~~ちなみに、以下のような抽選方法だと席の数のループだけで結果が得られます。
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なお、「席1と席2に6番の人だけが応募する」というような、結果が得られない組み合わせは考慮していません。
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~~
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```Phthon
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import random
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@@ -27,6 +32,8 @@
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seats = [seat_1,seat_2,seat_3,seat_4,seat_5,
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seat_6]
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seats = [[1,3],[1,2],[1,2]] # だめなケースを追記
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# (席番号, 候補リスト)に整形
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seats = [(i+1,v) for i,v in enumerate(seats)]
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