回答編集履歴
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@@ -1,7 +1,43 @@
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欲しい結果は以下のようなものでしょうか。
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```Python
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import pandas as pd
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df1 = pd.DataFrame({'Date1':['2019-01-01','2019-01-02','2019-01-03'], 'value1':[1,2,3]})
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7
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df2 = pd.DataFrame({'Date2':['2019-01-01','2019-01-03'], 'value2':[10,30]})
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df1['Date1'] = pd.to_datetime(df1['Date1'])
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df2['Date2'] = pd.to_datetime(df2['Date2'])
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print(df1)
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# Date1 value1
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12
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#0 2019-01-01 1
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#1 2019-01-02 2
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#2 2019-01-03 3
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print(df2)
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# Date2 value2
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#0 2019-01-01 10
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#1 2019-01-03 30
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# 両方に存在する日付のみ抽出
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s = set(df1['Date1']) & set(df2['Date2'])
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df1 = df1[df1['Date1'].isin(s)]
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print(df1)
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# Date1 value1
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#0 2019-01-01 1
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#2 2019-01-03 3
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df2 = df2[df2['Date2'].isin(s)]
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30
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print(df2)
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# Date2 value2
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#0 2019-01-01 10
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#1 2019-01-03 30
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```
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質問修正前の回答
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37
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-----
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38
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```Python
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39
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import pandas as pd
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df = pd.DataFrame({'Date1':['2019-01-01','2019-01-03',''], 'Date2':['2019-01-01','2019-01-02','2019-01-03']})
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df['Date1'] = pd.to_datetime(df['Date1'])
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43
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df['Date2'] = pd.to_datetime(df['Date2'])
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