回答編集履歴
2
ipythonのからpythonのコードに変換
answer
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@@ -1,22 +1,23 @@
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`tuple()`を使えばいいだけのような。
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```python
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4
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-
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4
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import pandas as pd
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5
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-
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5
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import numpy as np
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6
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6
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df = pd.DataFrame({"A":np.arange(1, 8),
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7
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-
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7
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"B":np.arange(10, 80, 10)}
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8
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8
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)
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9
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9
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print(df)
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10
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Out[4]:
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11
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A B
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0 1 10
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1 2 20
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14
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2 3 30
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15
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3 4 40
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4 5 50
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5 6 60
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6 7 70
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10
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# A B
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# 0 1 10
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# 1 2 20
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# 2 3 30
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# 3 4 40
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# 4 5 50
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# 5 6 60
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# 6 7 70
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-
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A = tuple(df["A"])
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print(A)
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-
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# (1, 2, 3, 4, 5, 6, 7)
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```
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1
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answer
CHANGED
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@@ -17,6 +17,6 @@
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5 6 60
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6 7 70
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20
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In [
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In [5]: tuple(df["A"])
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Out[
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Out[5]: (1, 2, 3, 4, 5, 6, 7)
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```
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