Pythonで1つの共通ワードを基に複数リストの値を出す方法

こんにちは。
問題のような質問になってしまい、申し訳ないですが、
例えばですが、下記に A/B/C と3つのリストがあり、

A ["りんご","なし","ぶどう","みかん"] = ["1","3","5","7"]
B ["りんご","もも","バナナ","オレンジ"] = ["2","4","6","8"]
C ["りんご","いちご","柿","パイナップル"] = ["4","6","8","10"]

ここから"りんご"をA/B/Cの共通ワードにして、最終的に

["りんご","なし","ぶどう","みかん"] = ["4","12","20","28"]
["りんご","もも","バナナ","オレンジ"] = ["4","8","12","16"]
["りんご","いちご","柿","パイナップル"] = ["4","6","8","10"]

と言った、Cを基準にした場合、りんごの"4"に合わせてほかの果物もAだったら4倍、
Bだったら2倍にする方法をご教授いただけると幸いです。

よろしくお願いいたします。

sky6720

2022/05/27 07:23 編集

リストCが基準なのは確定なんですかね？あとかならず倍率が整数倍になるとして、下記のような感じですか？ ```python listA = ["りんご","なし","ぶどう","みかん"] listB = ["りんご","もも","バナナ","オレンジ"] listC = ["りんご","いちご","柿","パイナップル"] df1 = ["1","3","5","7"] df2 = ["2","4","6","8"] df3 = ["4","6","8","10"] KeyWord = 'りんご' #それぞれのリストの中でのキーワードのインデックスを求める indexA = listA.index(KeyWord) indexB = listB.index(KeyWord) indexC = listC.index(KeyWord) #listCを基準に何倍にすればよいかを求める(ここでは整数倍としています) CperA = int(df3[indexC]) // int(df1[indexA]) CperB = int(df3[indexC]) // int(df2[indexB]) #リスト内包表記で各要素に倍率をかけて新しいリストにする newA = [int(n) * CperA for n in df1] newB = [int(n) * CperB for n in df2] print(f'{listA} = {newA}') print(f'{listB} = {newB}') print(f'{listC} = {df3}') ```

Mako11

2022/05/29 02:28

ありがとうございます！リストCの基準で問題ありませんでしたが、質問しようとしたところ別の方の回答で解決ができました！！

行動規範の内容に同意します

回答1件

ベストアンサー

python
1listA = ["りんご","なし","ぶどう","みかん"]  
2listB = ["りんご","もも","バナナ","オレンジ"]    
3listC = ["りんご","いちご","柿","パイナップル"] 
4
5df1 = ["1","3","5","7"]
6df2 = ["2","4","6","8"]
7df3 = ["4","6","8","10"]
8
9df1 = [*map(float, df1)]
10df2 = [*map(float, df2)]
11df3 = [*map(float, df3)]
12
13keyword = "りんご"
14base = df3[listC.index(keyword)]
15ratio = [base/v[l.index(keyword)] for l, v in zip((listA, listB, listC), (df1, df2, df3))]
16df1, df2, df3 = [[str(ratio[i]*v) for v in l] for i, l in enumerate((df1, df2, df3))]
17
18print(f'{df1 = }')
19print(f'{df2 = }')
20print(f'{df3 = }')
21
22#
23df1 = ['4.0', '12.0', '20.0', '28.0']
24df2 = ['4.0', '8.0', '12.0', '16.0']
25df3 = ['4.0', '6.0', '8.0', '10.0']