シェルスクリプトの実行時に[:missing]がでる原因がわからない

Question

シェルスクリプトを実行すると下記エラーが出てきます。
シェトしては列の並び替えを行っています。

Jan 5 15:45:05:, ,,,2017/01/05 15:45:05,,extauth,,122.122.5.3,3C:75:65:83:C2:1F,,,,,adc

2017/01/05 15:45:05
Jan 5 15:45:19:, ,(̤����),2017/01/05 15:45:19,,,extauth,,133.122.2.3,67:77:dd:e4:32:14,0,,ja-JP,Mozilla/5.0 (Linux; Android 4.4.4; 404KC Build/107.0.2b10) AppleWebKit/537.36 (KHTML, like Gecko) Ch,496
2017/01/05 15:45:19

./sample.sh: 12: [: missing ]
Jan 5 15:45:21:, ,,,2017/01/05 15:45:21,,extauth,,111.148.3.6,88:33:33:66:33:D3,,,,,ab5

2017/01/05 15:45:21
Jan 5 15:46:39:, ,,,2017/01/05 15:46:39,,extauth,,199.122.0.0,66:77:66:88:22:3F,,,,,496

2017/01/05 15:46:39
Jan 5 15:46:50:, ,(̤����),2017/01/05 15:46:50,,,extauth,,111.133.2.8,66:33:22:88:11:1F,0,,ja-JP,Mozilla/5.0 (Linux; Android 4.4.4; 404KC Build/107.0.2b10) AppleWebKit/537.36 (KHTML, like Gecko) Ch,c9d
2017/01/05 15:46:50

./sample.sh: 12: [: missing ]
Jan 5 15:47:06:, ,(̤����),2017/01/05 15:47:06,,,extauth,,133.122.5.4,88:33:33:33:33:33,0,,ja-JP,Mozilla/5.0 (Linux; Android 6.0.1; Nexus 5 Build/M4B30X) AppleWebKit/537.36 (KHTML, like Gecko) Chro,a62
2017/01/05 15:47:06

./sample.sh: 12: [: missing ]
Jan 5 15:47:58:, ,,,2017/01/05 15:47:58,,extauth,,192.168.1.7,88:77:77:77:66:66,,,,,a62

2017/01/05 15:47:58
Jan 5 15:47:58:, ,,,2017/01/05 15:47:58,,extauth,,111.122.7.5,GG:FF:DD:VV:CC:1D,,,,,cdf

2017/01/05 15:47:58
Jan 5 15:48:24:, ,(̤����),2017/01/05 15:48:24,,,extauth,,111.133.3.6,66:66:66:84:C2:11,0,,ja-JP,Mozilla/5.0 (Linux; Android 4.4.4; 404KC Build/107.0.2b10) AppleWebKit/537.36 (KHTML, like Gecko) Ch,4444
2017/01/05 15:48:24

./sample.sh: 12: [: missing ]
Jan 5 15:49:02:, ,,,2017/01/05 15:49:02,,extauth,,188.188.2.0,CC:BB:CC:84:C2:1F,,,,,447

2017/01/05 15:49:02
join: 無効なフィールド番号です: `{1-18}'

おそらく変な文字列が含まれているときにエラーが出ているので
それが原因かと思いますが、どう修正すればよろしいでしょうか？

#!/bin/sh
user_agent=`cat authlog_tail | cut -d, -f 14- | rev | cut -d, -f 2- | rev`

while read row; do
    echo ${row}
    echo ${row} | cut -d, -f4
    echo ${row} | cut -d, -f5
    start_col=`echo ${row} | cut -d, -f4`
    end_col=`echo ${row} | cut -d, -f5`

    # レコードが認証開始か認証終了かで処理を分ける
    if [ -n "$start_col"]; then
        echo ${row} | awk -F, -vOFS=, '{print $1,"",$NF,"0","",$11,"","",$9,"",$10,$4,$7,$8,"","",$13,"","","","",$6,$12,"","","","","","",""}' >> result.csv
        #echo ${row} | awk -F, -vOFS=, '{print $1,"",$NF,"0","",$11,"","",$9,"",$10,$4,$7,$8,"","",$13,""}' >> front.csv
        #echo ${row} | awk -F, -vOFS=, '{print "","",$6,$12,"","","","","","",""}' >> behind.csv
    elif [ -n "$end_col"]; then
        echo ${row} | awk -F, -vOFS=, '{print $1,"",$NF,"1","",$11,"","",$9,"",$10,$5,$7,$8,"","",$13,"","","","",$6,$12,"","","","","","",""}' >> result.csv
        #echo ${row} | awk -F, -vOFS=, '{print $1,"",$NF,"1","",$11,"","",$9,"",$10,$4,$7,$8,"","",$13,""}' >> front.csv
        #echo ${row} | awk -F, -vOFS=, '{print "","",$6,$12,"","","","","","",""}' >> behind.csv
    else
        echo `date "+[%Y-%m-%d %H:%M:%S][Failed] Begin $row"`
    fi
done < authlog_tail

join -o 1.{1-18},2.1,1.{20-} $result.csv $user_agent
#join -o 1.{1-13},2.1,1.{15-} $front $user_agent $behind

Answer 1

誤）
    if [ -n "$start_col"]; then
正）
    if [ -n "$start_col" ]; then

スペースを開けましょう。

Comments

[kozica]

なるほど！
シェルは最近触り始めたので、そういったルールがまだわかっていませんでした、、、
ありがとうございます！

Answer 2

[: missing ]

[を閉じる]が無いよというエラーです。]の前に空白がないのが原因です。

Comments

[otn]

> join: 無効なフィールド番号です: `{1-18}'
にもエラーが出てますね。
おそらく、範囲指定をしたいと言う事だと思います。
joinの機能ではなくシェルの機能で、{1..18}ならＯＫです。その際、必ずフィールドはカンマでなく空白で区切ってください。
{20..}のような終わり指定無しは無理。

[kozica]

指摘ありがとうございます！
参考になりました！