回答編集履歴
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1
answer
CHANGED
@@ -1,6 +1,6 @@
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1
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元のソースを活かすならこんなかんじですかね
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```python
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3
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-
l_in = [s.count('1') for s in l]
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3
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+
l_in = [str(s).count('1') for s in l]
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b = sum(l_in)
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```
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