回答編集履歴
2
追加
answer
CHANGED
@@ -9,4 +9,41 @@
|
|
9
9
|
//配列prime_structureの定義
|
10
10
|
unsigned int * prime_structure;
|
11
11
|
prime_structure = (int *)calloc(result_int,sizeof(int));
|
12
|
+
```
|
13
|
+
エラトステネスの篩に興味が涌き、参考に部分作成してみました
|
14
|
+
```C
|
15
|
+
#include <stdio.h>
|
16
|
+
#include <math.h>
|
17
|
+
#include <stdlib.h>
|
18
|
+
|
19
|
+
int main(void){
|
20
|
+
|
21
|
+
double a_double = 9;
|
22
|
+
double b_double = 2;
|
23
|
+
unsigned int a_int,b_int,result_int;
|
24
|
+
|
25
|
+
result_int = pow(a_double,b_double);
|
26
|
+
|
27
|
+
a_int = a_double;
|
28
|
+
b_int = b_double;
|
29
|
+
|
30
|
+
//配列prime_structureの定義
|
31
|
+
unsigned int * prime_structure;
|
32
|
+
prime_structure = (int *)calloc(result_int-1,sizeof(int));
|
33
|
+
|
34
|
+
unsigned int i,j;
|
35
|
+
//エラトステネスのふるい
|
36
|
+
for (i = 2; i < result_int/2 ; i++) {
|
37
|
+
if (prime_structure[i] == 0){// prime[i]が素数なら
|
38
|
+
for (j = 2; i * j <= result_int-1; j++){
|
39
|
+
prime_structure[i * j] = 1; // 素数の倍数は素数ではない
|
40
|
+
}
|
41
|
+
}
|
42
|
+
}
|
43
|
+
for ( i = 1; i < result_int; i++){
|
44
|
+
if(prime_structure[ i ] == 0){
|
45
|
+
printf("%dは、素数\n",i);
|
46
|
+
}
|
47
|
+
}
|
48
|
+
}
|
12
49
|
```
|
1
訂正
answer
CHANGED
@@ -8,5 +8,5 @@
|
|
8
8
|
```
|
9
9
|
//配列prime_structureの定義
|
10
10
|
unsigned int * prime_structure;
|
11
|
-
prime_structure = (int *)calloc(result_int
|
11
|
+
prime_structure = (int *)calloc(result_int,sizeof(int));
|
12
12
|
```
|