回答編集履歴
2
jQuery\.prototype\.concat \(独自拡張\)
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@@ -1,4 +1,8 @@
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### Array.prototype.join
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セレクタを結合する
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2つ以上のセレクタを結合する。
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@@ -26,6 +30,38 @@
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jQuery(selectors.join()).on('click', handleClick);
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</script>
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```
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### jQuery.prototype.add
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2つのjQueryオブジェクトを結合する。
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```HTML
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<p id="aaa">aaa</p>
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<p id="bbb">bbb</p>
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<script type="text/javascript">
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'use stirct';
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function handleClick (event) {
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console.log(event.type);
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}
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var a = jQuery('#aaa'), b = jQuery('#bbb');
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@@ -38,4 +74,90 @@
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### jQuery.prototype.concat (独自拡張)
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3つ以上のjQueryオブジェクトを結合する。
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- [jQuery.prototype.concat - JSFiddle](https://jsfiddle.net/wLfhu8Ls/1/)
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```HTML
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<p id="aaa">aaa</p>
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<p id="bbb">bbb</p>
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<p id="ccc">ccc</p>
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<script type="text/javascript">
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'use stirct';
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function handleClick (event) {
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console.log(event.type);
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}
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console.log(jQuery.prototype.concat);
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Object.defineProperty(jQuery.prototype, 'concat', {
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writable: true,
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enumerable: false,
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configurable: true,
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value: function concat (elements) {
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var clones = jQuery(this),
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push = this.push;
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for (var i = 0, l = arguments.length; i < l; ++i) {
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push.apply(clones, arguments[i]);
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}
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return clones;
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}
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});
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var a = jQuery('#aaa'), b = jQuery('#bbb'), c = jQuery('#ccc');
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jQuery(a.concat(b, c)).on('click', handleClick);
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console.dir(a.concat(b, c));
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console.dir(a);
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</script>
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```
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Re: k499778 さん
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1
セレクタ用変数の変数名を変更
test
CHANGED
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@@ -22,9 +22,9 @@
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var
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var selectors = ['#aaa', '#bbb'];
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jQuery(
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jQuery(selectors.join()).on('click', handleClick);
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