回答編集履歴
2
No need to fill s\[j\] by '\\0'\.
answer
CHANGED
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@@ -10,7 +10,8 @@
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10
10
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j++;
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11
11
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}
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12
12
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}
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13
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-
s[j] = '\0';
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14
13
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s.resize(j);
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15
14
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}
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16
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-
```
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15
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+
```
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16
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+
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17
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+
Without resizing, this string is not null-terminating.
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1
Fixed to be null-terminated string\.
answer
CHANGED
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@@ -10,6 +10,7 @@
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10
10
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j++;
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11
11
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}
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12
12
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}
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13
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+
s[j] = '\0';
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13
14
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s.resize(j);
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14
15
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}
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15
16
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```
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