回答編集履歴
2
No need to fill s\[j\] by '\\0'\.
test
CHANGED
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@@ -22,10 +22,12 @@
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22
22
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}
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-
s[j] = '\0';
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-
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25
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s.resize(j);
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28
26
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27
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}
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28
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29
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```
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30
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+
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31
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+
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32
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+
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33
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+
Without resizing, this string is not null-terminating.
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1
Fixed to be null-terminated string\.
test
CHANGED
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@@ -22,6 +22,8 @@
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22
22
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23
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}
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24
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25
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+
s[j] = '\0';
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26
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+
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27
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s.resize(j);
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28
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}
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