回答編集履歴
2
微修正
answer
CHANGED
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@@ -5,7 +5,7 @@
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5
5
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int len = 0;
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6
6
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while(*s++)
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7
7
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len++;
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8
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-
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8
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+
return len;
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9
9
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}
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10
10
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11
11
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int main(void) {
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1
修正
answer
CHANGED
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@@ -3,10 +3,9 @@
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3
3
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4
4
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int str_length(const char *s) {
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5
5
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int len = 0;
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6
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-
while
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6
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+
while(*s++)
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7
7
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len++;
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8
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-
}
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9
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-
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8
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+
return len;
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10
9
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}
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11
10
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12
11
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int main(void) {
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@@ -18,9 +17,9 @@
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18
17
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19
18
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int k = str_length(t); // k = tの長さ
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20
19
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for ( int i = 0; i < k; i++ ) {
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21
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-
str
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20
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+
*(str+i) = *(t+k-i-1);
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22
21
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}
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23
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-
str
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22
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+
*(str+k) = '\0';
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24
23
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25
24
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printf("str2の文字列は %s です．\n", str);
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26
25
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}
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