回答編集履歴
2
回答を追記
answer
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@@ -77,4 +77,113 @@
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WHERE sub.data IS NULL
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) AS l ON h.shop_id = l.shop_id AND h.head = l.head;
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-
```
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```
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---
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いろいろ想像で補った部分がありますが、《結果01》を経由して《結果02》を得るためのSQLは、以下のようになります。
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```sql
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# ④
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SELECT
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h.jan,
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h.head AS price_type,
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h.product_name_id AS max_product_name_id,
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# ⑤
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CASE l.product_name_id
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WHEN h.product_name_id THEN 0
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ELSE l.product_name_id
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END AS min_product_name_id,
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h.data AS price_max,
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# ⑤
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CASE l.data
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WHEN h.data THEN 0
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ELSE l.data
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END AS price_min,
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(h.data - l.data) AS price_diff
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FROM (
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# ②
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SELECT main.*
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FROM (
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# ①
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SELECT t1.*
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FROM product_jans AS t1
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LEFT JOIN product_jans AS t2 ON
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t1.shop_id = t2.shop_id
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AND t1.jan = t2.jan
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AND t1.head = t2.head
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AND t1.modified < t2.modified
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WHERE t2.modified IS NULL
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) AS main
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LEFT OUTER JOIN (
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# ①
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SELECT t1.*
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FROM product_jans AS t1
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LEFT JOIN product_jans AS t2 ON
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t1.shop_id = t2.shop_id
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AND t1.jan = t2.jan
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AND t1.head = t2.head
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AND t1.modified < t2.modified
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WHERE t2.modified IS NULL
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) AS sub ON
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main.jan = sub.jan
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AND main.head = sub.head
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AND main.data < sub.data
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WHERE sub.data IS NULL
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) AS h
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LEFT OUTER JOIN (
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# ③
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SELECT main.*
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FROM (
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# ①
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SELECT t1.*
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FROM product_jans AS t1
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LEFT JOIN product_jans AS t2 ON
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t1.shop_id = t2.shop_id
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AND t1.jan = t2.jan
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AND t1.head = t2.head
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AND t1.modified < t2.modified
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WHERE t2.modified IS NULL
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) AS main
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LEFT OUTER JOIN (
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# ①
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SELECT t1.*
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FROM product_jans AS t1
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LEFT JOIN product_jans AS t2 ON
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t1.shop_id = t2.shop_id
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AND t1.jan = t2.jan
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AND t1.head = t2.head
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AND t1.modified < t2.modified
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WHERE t2.modified IS NULL
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) AS sub ON
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main.jan = sub.jan
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AND main.head = sub.head
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AND main.data > sub.data
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WHERE sub.data IS NULL
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) AS l ON h.jan = l.jan AND h.head = l.head;
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```
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以下の条件で、データを抽出・整形しています。
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斜体字の部分が、私が想像で補った箇所です。
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① __jan、shop_id__、"新品・中古・コレクター"価格の組み合わせごとに`modified`が最新の行を抽出
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② ①の中から、__jan__、"新品・中古・コレクター"価格の組み合わせごとに最高値（`data`が最大）の行を抽出
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③ ①の中から、__jan__、"新品・中古・コレクター"価格の組み合わせごとに最安値（`data`が最小）の行を抽出
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④ ②、③を、__jan__、"新品・中古・コレクター"価格の組み合わせごとに１行に結合し、最高値と最安値、さらにそのそれぞれの商品名コード、価格差を取得
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⑤ その際、最高値と最安値が一致している行は最安値の商品名コードと価格を"0"と表示
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なお、どこから出てきたか不明なため、《結果02》の`id`カラムは無視しています。
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1
未完成の回答を追記
answer
CHANGED
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@@ -17,4 +17,64 @@
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17
17
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例えば`product_name_id` = 20493 は、新品価格・中古価格・コレクター価格の`modified`が
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いずれも"2016-04-05 07:38:02"になっていますが、
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これが1秒でもズレることはないという認識で問題ないか、という意味です。
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20
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この前提が誤っていると、そもそも《結果01》を取得するSQLから見直す必要があるかもしれません。
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この前提が誤っていると、そもそも《結果01》を取得するSQLから見直す必要があるかもしれません。
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---
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※まだ未完成です。うまく動きません。
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```sql
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SELECT
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h.jan,
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h.product_name_id AS max_product_name_id,
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l.product_name_id AS min_product_name_id,
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h.data AS price_max,
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l.data AS price_min,
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(h.data - l.data) AS price_diff
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FROM (
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# ②
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SELECT main.*
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FROM product_jans AS main
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LEFT OUTER JOIN (
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# ①
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SELECT t1.*
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FROM product_jans AS t1
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LEFT JOIN product_jans AS t2 ON
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t1.shop_id = t2.shop_id
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AND t1.product_name_id = t2.product_name_id
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AND t1.head = t2.head
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AND t1.modified < t2.modified
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WHERE t2.modified IS NULL
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) AS sub ON
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main.shop_id = sub.shop_id
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AND main.head = sub.head
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AND main.data < sub.data
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WHERE sub.data IS NULL
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) AS h
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LEFT OUTER JOIN (
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# ③
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SELECT main.*
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FROM product_jans AS main
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LEFT OUTER JOIN (
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# ①
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SELECT t1.product_name_id, t1.jan, t1.head, t1.data, t1.shop_id
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FROM product_jans AS t1
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LEFT JOIN product_jans AS t2 ON
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t1.shop_id = t2.shop_id
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AND t1.product_name_id = t2.product_name_id
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AND t1.head = t2.head
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AND t1.modified < t2.modified
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WHERE t2.modified IS NULL
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) AS sub ON
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main.shop_id = sub.shop_id
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AND main.head = sub.head
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AND main.data > sub.data
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WHERE sub.data IS NULL
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) AS l ON h.shop_id = l.shop_id AND h.head = l.head;
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```
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