回答編集履歴
4
追記
test
CHANGED
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@@ -116,6 +116,46 @@
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116
116
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117
117
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dst[-1].append(i)
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118
118
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119
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-
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119
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+
```
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120
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+
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121
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122
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123
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さらに追記
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124
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125
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---
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126
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127
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普通に読み辛いですし効率面も特段良くありませんが、個人的にはこういうのが好きです。
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128
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+
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129
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+
おまけです。
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130
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131
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132
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133
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```Python
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134
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135
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+
indice_1 = (
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136
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137
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i for i, e in enumerate(src)
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138
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+
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139
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if e == 1
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140
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+
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141
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)
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142
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143
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dst = [
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144
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145
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+
[idx, *map(operator.itemgetter(0), zip(
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146
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147
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itertools.count(idx+1),
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148
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149
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itertools.takewhile(
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150
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151
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lambda e: e == 2, src[idx+1:]
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152
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153
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)
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154
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155
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))]
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156
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+
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157
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for idx in indice_1
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158
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159
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]
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120
160
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121
161
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```
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3
追記
test
CHANGED
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@@ -79,3 +79,43 @@
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79
79
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i += 1
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80
80
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81
81
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```
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82
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83
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84
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85
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+
for文を使うなら二回に分けた方が無駄が少ないように思います。
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86
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+
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87
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+
```Python
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88
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89
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dst = []
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90
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91
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92
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93
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it = (
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94
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95
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i for i, e in enumerate(src)
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96
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97
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if e == 1
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98
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+
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99
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)
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100
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101
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for index_1 in it:
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102
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103
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dst.append([index_1])
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104
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105
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106
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+
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107
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idx = index_1 + 1
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108
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+
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109
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for i, e in enumerate(src[idx:], start=idx):
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110
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111
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if e != 2:
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112
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113
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break
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114
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+
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115
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+
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116
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117
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dst[-1].append(i)
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118
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+
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119
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120
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+
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121
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+
```
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2
追記
test
CHANGED
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@@ -39,3 +39,43 @@
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39
39
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[[6], [9, 10, 11]]
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40
40
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41
41
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```
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42
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+
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43
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+
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44
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45
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+
コメントを受けて
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46
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47
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+
---
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48
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49
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+
例えば、こんなふうに。
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50
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51
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+
```Python
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52
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+
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53
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dst = []
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54
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+
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55
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+
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56
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+
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57
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i = 0
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58
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+
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59
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while i < len(src):
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60
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+
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61
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if src[i] != 1:
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62
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+
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63
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+
i += 1
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64
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65
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continue
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66
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+
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67
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+
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68
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+
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69
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dst.append([i])
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70
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+
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71
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i += 1
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72
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+
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73
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+
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74
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+
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75
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+
while i < len(src) and src[i] == 2:
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76
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+
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77
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+
dst[-1].append(i)
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78
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+
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79
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+
i += 1
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80
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+
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81
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+
```
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1
追記
test
CHANGED
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@@ -8,7 +8,11 @@
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8
8
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9
9
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10
10
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11
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-
src = [4,
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11
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+
src = [4,4,2,4,5,3,1,3,4,1,2,2,3]
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12
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+
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13
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+
assert all(len(str(e)) == 1 for e in src) # srcの全要素は1桁
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14
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+
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15
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+
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12
16
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13
17
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dst = [
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14
18
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@@ -28,14 +32,10 @@
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28
32
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29
33
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30
34
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31
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-
**実行結果** [Wandbox](https://wandbox.org/permlink/
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35
|
+
**実行結果** [Wandbox](https://wandbox.org/permlink/SVnsvzydmFuJXlyh)
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32
36
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33
37
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```
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34
38
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35
39
|
[[6], [9, 10, 11]]
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36
40
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37
41
|
```
|
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38
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-
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39
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-
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40
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-
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41
|
-
srcの全ての要素が1桁の整数との前提です。
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