回答編集履歴
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追記
test
CHANGED
@@ -99,3 +99,47 @@
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group by M.last_date;
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```
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----
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> 累積の新規ユーザ数の左隣りに、その月の新規ユーザ数も表示させたいのですが
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```sql
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select
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date_format(M.last_date, '%Y/%m') as mon,
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count(*) as tcnt,
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sum(last_day(M.last_date) = last_day(U.user_date)) as mcnt
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from (
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select distinct last_day(access_day) as last_date from access_record
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) as M
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join (
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select user_id, min(access_day) as user_date from access_record group by user_id
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) as U
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where M.last_date >= U.user_date
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group by M.last_date;
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```
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