回答編集履歴
1
追記
answer
CHANGED
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@@ -23,4 +23,36 @@
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23
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printf("\n");
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return 0;
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}
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26
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```
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27
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[追記] 少なからず小賢しい修正。第二引数:tokensにNULLを渡せば分割数が返ってくるので...:
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28
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```C
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29
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#include <stdio.h>
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#include <stdlib.h>
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31
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#include <string.h>
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32
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33
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int split(char* str, char* tokens[], const char* delim) {
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char* last = str + strlen(str);
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int count = 0;
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36
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for ( char* token = strtok(str, delim); token; token = strtok(NULL, delim)) {
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if ( tokens ) { tokens[count] = token; }
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else { token[strlen(token)] = *delim; *last = '\0'; }
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++count;
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}
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return count;
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}
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int main() {
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char input[] = "きょうは,とても,いい天気";
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char** tokens;
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int n = split(input, NULL, ","); // token数を求め
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tokens = malloc(sizeof(char*)*n); // そんだけの領域を確保して
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split(input, tokens, ","); // もっかい呼ぶ
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int i;
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51
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for ( i = 0; i < n; ++i ) {
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printf("[%s] ", tokens[i]);
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}
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printf("\n");
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free(tokens);
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return 0;
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}
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```
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