回答編集履歴
1
修正
test
CHANGED
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@@ -31,3 +31,107 @@
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mfcc = getMfcc('%s.wav' % (artist, song))
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```
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## 追記
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> call（フォルダ）のcall01.wav、call02.wav…call05.wav（wavファイル）とbell（フォルダ）の中にあるbell01、bell02…bell13.wav（wavファイル）を探すようにすることは可能でしょうか？
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とりあえず正しいパスを書式指定子で作成するのであれば、以下のようにすればいいと思います。
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```python
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artists = ["bell", "call"]
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songs = [
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[
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"bell01",
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"bell02",
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"bell03",
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"bell04",
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"bell05",
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"bell07",
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"bell08",
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"bell09",
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"bell10",
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"bell11",
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"bell12",
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"bell13",
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],
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["call01", "call02", "call03", "call04", "call05"],
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]
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for artist, artist_songs in zip(artists, songs):
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for song in artist_songs:
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path = "%s/%s.wav" % (artist, song)
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print(path)
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```
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```
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bell/bell01.wav
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bell/bell02.wav
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bell/bell03.wav
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bell/bell04.wav
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bell/bell05.wav
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bell/bell07.wav
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bell/bell08.wav
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bell/bell09.wav
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bell/bell10.wav
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bell/bell11.wav
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bell/bell12.wav
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bell/bell13.wav
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call/call01.wav
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call/call02.wav
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call/call03.wav
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call/call04.wav
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call/call05.wav
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```
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