回答編集履歴
3
修正
answer
CHANGED
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@@ -7,7 +7,7 @@
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7
7
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```
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8
8
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9
9
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どんな式でも実行してしまうevalに比べ、
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10
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-
ast.literal_evalはリテラル形式の文字列しかパースしないので安全です。
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10
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+
ast.literal_evalはリテラル形式の文字列しかパースしないので比較的安全です。
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11
11
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```Python
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12
12
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>>> password = 'MY_SECRET_PASSWORD'
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13
13
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>>> eval(input())
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2
例の統一
answer
CHANGED
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@@ -30,8 +30,8 @@
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30
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>>>
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31
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>>> password = 'MY_SECRET_PASSWORD'
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32
32
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>>> literal_eval(input())
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33
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-
(
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33
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+
(2, 3)
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34
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-
(
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34
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+
(2, 3)
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35
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>>> literal_eval(input())
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36
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print(*('{}: {}'.format(k, v) for k, v in locals().items()), sep='\n')
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37
37
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Traceback (most recent call last):
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1
修正
answer
CHANGED
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@@ -11,8 +11,8 @@
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11
11
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```Python
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12
12
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>>> password = 'MY_SECRET_PASSWORD'
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13
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>>> eval(input())
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14
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-
2
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14
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+
(2, 3)
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15
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-
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15
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+
(2, 3)
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16
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>>> eval(input())
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17
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print(*('{}: {}'.format(k, v) for k, v in locals().items()), sep='\n')
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18
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__name__: __main__
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@@ -23,4 +23,20 @@
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23
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__annotations__: {}
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24
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__builtins__: <module 'builtins' (built-in)>
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25
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password: MY_SECRET_PASSWORD
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26
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+
```
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27
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+
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28
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+
```Python
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29
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+
>>> from ast import literal_eval
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30
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+
>>>
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31
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+
>>> password = 'MY_SECRET_PASSWORD'
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32
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+
>>> literal_eval(input())
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33
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+
(1, 2)
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34
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+
(1, 2)
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35
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+
>>> literal_eval(input())
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36
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+
print(*('{}: {}'.format(k, v) for k, v in locals().items()), sep='\n')
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37
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Traceback (most recent call last):
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38
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+
File "<stdin>", line 1, in <module>
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39
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+
File "C:...\ast.py", line 99, in literal_eval
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40
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...
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41
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ValueError: malformed node or string: <_ast.Call object at 0x0000018D769DCF10>
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26
42
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```
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