回答編集履歴
3
追加
    
        answer	
    CHANGED
    
    | @@ -20,4 +20,26 @@ | |
| 20 20 | 
             
              } while(card != '\0');
         | 
| 21 21 | 
             
              printf("%c\n", i + P);
         | 
| 22 22 | 
             
            }
         | 
| 23 | 
            +
            ```
         | 
| 24 | 
            +
             | 
| 25 | 
            +
            do-while は for に纏めれば小さくなりますね.
         | 
| 26 | 
            +
            ```c
         | 
| 27 | 
            +
            #include <stdio.h>
         | 
| 28 | 
            +
             | 
| 29 | 
            +
            #define N 3 /*人数*/
         | 
| 30 | 
            +
            #define M 100 /*最大枚数*/
         | 
| 31 | 
            +
            #define C 'a' /*カード(オフセット)*/
         | 
| 32 | 
            +
            #define P 'A' /*参加者(オフセット)*/
         | 
| 33 | 
            +
             | 
| 34 | 
            +
            int main(int argc, char *argv[]) {
         | 
| 35 | 
            +
              int i, top[N]={0};
         | 
| 36 | 
            +
              char card, S[N][M+1];
         | 
| 37 | 
            +
              //入力
         | 
| 38 | 
            +
              for(i=0;i<N;i++) scanf("%s", S[i]);
         | 
| 39 | 
            +
              //勝負
         | 
| 40 | 
            +
              for(card=C; card!='\0'; card=S[i][top[i]++]) i = card - C;
         | 
| 41 | 
            +
              //出力
         | 
| 42 | 
            +
              printf("%c\n", i + P);
         | 
| 43 | 
            +
            }
         | 
| 44 | 
            +
             | 
| 23 45 | 
             
            ```
         | 
2
コードを読み易く(?)
    
        answer	
    CHANGED
    
    | @@ -2,19 +2,22 @@ | |
| 2 2 | 
             
            ```c
         | 
| 3 3 | 
             
            #include <stdio.h>
         | 
| 4 4 |  | 
| 5 | 
            +
            #define N 3 /*人数*/
         | 
| 6 | 
            +
            #define M 100 /*最大枚数*/
         | 
| 7 | 
            +
            #define C 'a' /*カード(オフセット)*/
         | 
| 8 | 
            +
            #define P 'A' /*参加者(オフセット)*/
         | 
| 9 | 
            +
             | 
| 5 10 | 
             
            int main(int argc, char *argv[]) {
         | 
| 6 | 
            -
              int i,  | 
| 11 | 
            +
              int i, top[N]={0};
         | 
| 7 | 
            -
              char  | 
| 12 | 
            +
              char card, S[N][M+1];
         | 
| 8 13 |  | 
| 9 | 
            -
              scanf("%s", S[ | 
| 14 | 
            +
              for(i=0;i<N;i++) scanf("%s", S[i]);
         | 
| 10 | 
            -
              scanf("%s", S[1]);
         | 
| 11 | 
            -
              scanf("%s", S[2]);
         | 
| 12 15 |  | 
| 13 | 
            -
               | 
| 16 | 
            +
              card = C;
         | 
| 14 17 | 
             
              do {
         | 
| 15 | 
            -
                i =  | 
| 18 | 
            +
                i = card - C;
         | 
| 16 | 
            -
                 | 
| 19 | 
            +
                card = S[i][top[i]++];
         | 
| 17 | 
            -
              } while( | 
| 20 | 
            +
              } while(card != '\0');
         | 
| 18 | 
            -
              printf("%c\n", i+ | 
| 21 | 
            +
              printf("%c\n", i + P);
         | 
| 19 22 | 
             
            }
         | 
| 20 23 | 
             
            ```
         | 
1
char 変数があったほうが分かり易い?
    
        answer	
    CHANGED
    
    | @@ -3,18 +3,18 @@ | |
| 3 3 | 
             
            #include <stdio.h>
         | 
| 4 4 |  | 
| 5 5 | 
             
            int main(int argc, char *argv[]) {
         | 
| 6 | 
            +
              int i, n[3]={0};
         | 
| 6 | 
            -
              char S[3][101];
         | 
| 7 | 
            +
              char c, S[3][101];
         | 
| 7 | 
            -
              int n[3] = {0};
         | 
| 8 8 |  | 
| 9 9 | 
             
              scanf("%s", S[0]);
         | 
| 10 10 | 
             
              scanf("%s", S[1]);
         | 
| 11 11 | 
             
              scanf("%s", S[2]);
         | 
| 12 12 |  | 
| 13 | 
            -
               | 
| 13 | 
            +
              c = 'a';
         | 
| 14 14 | 
             
              do {
         | 
| 15 | 
            -
                i = j;
         | 
| 16 | 
            -
                 | 
| 15 | 
            +
                i = c - 'a';
         | 
| 16 | 
            +
                c = S[i][n[i]++];
         | 
| 17 | 
            -
              } while( | 
| 17 | 
            +
              } while(c != '\0');
         | 
| 18 18 | 
             
              printf("%c\n", i+'A');
         | 
| 19 19 | 
             
            }
         | 
| 20 20 | 
             
            ```
         | 
