回答編集履歴
9
変数分離
answer
CHANGED
@@ -13,7 +13,7 @@
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|
13
13
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B = [['apple', 'ringo'],['banana', 'banana'],['orange', 'orenji'],['grape', 'budou']]
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14
14
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|
15
15
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a = {a[0]: a for a in A}
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16
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-
result = [[*a[
|
16
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+
result = [[*a[b0], b1] for b0, b1 in B if b0 in a]
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17
17
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print(result)
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18
18
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```
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19
19
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8
不要処理削除
answer
CHANGED
@@ -23,8 +23,6 @@
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|
23
23
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A = [['apple', 1],['banana', 2],['orange', 3],['grape', 4]]
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24
24
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B = [['apple', 'ringo'],['banana', 'banana'],['orange', 'orenji'],['grape', 'budou']]
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25
25
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26
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-
C = [b[0] for b in B]
|
27
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-
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28
26
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result = []
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29
27
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for b in B:
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30
28
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for a in A:
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7
辞書版追加
answer
CHANGED
@@ -6,6 +6,17 @@
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6
6
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print(result)
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7
7
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```
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8
8
|
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9
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+
データが大量にあるなら、二重ループは時間がかかり過ぎるので、辞書化した方がいいでしょう。
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10
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+
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11
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+
```python
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12
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+
A = [['apple', 1],['banana', 2],['orange', 3],['grape', 4],['x',0]]
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13
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+
B = [['apple', 'ringo'],['banana', 'banana'],['orange', 'orenji'],['grape', 'budou']]
|
14
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+
|
15
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+
a = {a[0]: a for a in A}
|
16
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+
result = [[*a[b[0]], b[1]] for b in B if b[0] in a]
|
17
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+
print(result)
|
18
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+
```
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19
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+
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9
20
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お書きになったコードで対応しました。
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10
21
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11
22
|
```python
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6
コード変更
answer
CHANGED
@@ -2,7 +2,7 @@
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2
2
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A = [['apple', 1],['banana', 2],['orange', 3],['grape', 4]]
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3
3
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B = [['apple', 'ringo'],['banana', 'banana'],['orange', 'orenji'],['grape', 'budou']]
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4
4
|
|
5
|
-
result = [[*a, b[1]] for b in B for a in A if
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5
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+
result = [[*a, b[1]] for b in B for a in A if a[0] == b[0]]
|
6
6
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print(result)
|
7
7
|
```
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8
8
|
|
5
コード変更
answer
CHANGED
@@ -2,8 +2,7 @@
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|
2
2
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A = [['apple', 1],['banana', 2],['orange', 3],['grape', 4]]
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3
3
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B = [['apple', 'ringo'],['banana', 'banana'],['orange', 'orenji'],['grape', 'budou']]
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4
4
|
|
5
|
-
b = dict(B)
|
6
|
-
result = [[
|
5
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+
result = [[*a, b[1]] for b in B for a in A if b[0] == a[0]]
|
7
6
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print(result)
|
8
7
|
```
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9
8
|
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4
バグ修正
answer
CHANGED
@@ -16,10 +16,10 @@
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16
16
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C = [b[0] for b in B]
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17
17
|
|
18
18
|
result = []
|
19
|
-
for
|
19
|
+
for b in B:
|
20
|
-
|
20
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+
for a in A:
|
21
|
-
|
21
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+
if a[0] == b[0]:
|
22
|
-
|
22
|
+
result.append([*a, b[1]])
|
23
23
|
|
24
24
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print(result)
|
25
25
|
```
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3
お書きになたコードの修正版を追加
answer
CHANGED
@@ -1,8 +1,25 @@
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1
|
-
```
|
1
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+
```python
|
2
2
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A = [['apple', 1],['banana', 2],['orange', 3],['grape', 4]]
|
3
3
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B = [['apple', 'ringo'],['banana', 'banana'],['orange', 'orenji'],['grape', 'budou']]
|
4
4
|
|
5
5
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b = dict(B)
|
6
6
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result = [[name, value, b[name]] for name, value in A if name in b]
|
7
7
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print(result)
|
8
|
+
```
|
9
|
+
|
10
|
+
お書きになったコードで対応しました。
|
11
|
+
|
12
|
+
```python
|
13
|
+
A = [['apple', 1],['banana', 2],['orange', 3],['grape', 4]]
|
14
|
+
B = [['apple', 'ringo'],['banana', 'banana'],['orange', 'orenji'],['grape', 'budou']]
|
15
|
+
|
16
|
+
C = [b[0] for b in B]
|
17
|
+
|
18
|
+
result = []
|
19
|
+
for c in C:
|
20
|
+
for a in A:
|
21
|
+
if a[0] == c:
|
22
|
+
result.append([*a, c])
|
23
|
+
|
24
|
+
print(result)
|
8
25
|
```
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2
変数名変更
answer
CHANGED
@@ -3,6 +3,6 @@
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|
3
3
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B = [['apple', 'ringo'],['banana', 'banana'],['orange', 'orenji'],['grape', 'budou']]
|
4
4
|
|
5
5
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b = dict(B)
|
6
|
-
result = [[name,
|
6
|
+
result = [[name, value, b[name]] for name, value in A if name in b]
|
7
7
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print(result)
|
8
8
|
```
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1
質問に対応
answer
CHANGED
@@ -3,6 +3,6 @@
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|
3
3
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B = [['apple', 'ringo'],['banana', 'banana'],['orange', 'orenji'],['grape', 'budou']]
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4
4
|
|
5
5
|
b = dict(B)
|
6
|
-
result = [[name, index, b[name]] for name, index in A]
|
6
|
+
result = [[name, index, b[name]] for name, index in A if name in b]
|
7
7
|
print(result)
|
8
8
|
```
|