回答編集履歴
3
ちょうせい
test
CHANGED
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@@ -71,3 +71,51 @@
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71
71
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|10|1|1|0|
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72
72
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73
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|20|1|0|0|
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74
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+
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75
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+
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76
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77
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# true/false
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78
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79
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カウントしていた結果を0より大きいかどうかで判断してはどうでしょうか？
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80
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+
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81
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+
```SQL
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82
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+
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83
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SELECT
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84
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+
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85
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+
user_id,
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86
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87
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+
SUM(CASE SUBSTRING(created_at, 1, 10)
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88
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89
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WHEN '2019-11-01' THEN 1
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90
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91
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ELSE 0
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92
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93
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END)>0 AS one_day,
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94
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95
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SUM(CASE SUBSTRING(created_at, 1, 10)
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96
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97
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WHEN '2019-11-02' THEN 1
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98
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+
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99
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ELSE 0
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100
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101
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END)>0 AS two_day,
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102
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+
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103
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SUM(CASE SUBSTRING(created_at, 1, 10)
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104
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105
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WHEN '2019-11-03' THEN 1
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106
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+
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107
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ELSE 0
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108
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109
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END)>0 AS three_day
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110
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+
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111
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FROM
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112
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113
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posts
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114
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+
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115
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WHERE
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116
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117
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DATE(SUBSTRING(created_at,1,10)) BETWEEN DATE('2019-11-01') AND DATE('2019-11-03')
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118
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+
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119
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GROUP BY user_id
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120
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+
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121
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```
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2
けっか
test
CHANGED
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@@ -59,3 +59,15 @@
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59
59
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GROUP BY user_id
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60
60
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61
61
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```
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62
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+
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63
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- 結果
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64
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+
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65
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+
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66
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+
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67
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|user_id|one_day|two_day|three_day|
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68
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+
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69
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|--:|--:|--:|--:|
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70
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+
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71
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|10|1|1|0|
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72
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+
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73
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|20|1|0|0|
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1
ちょうせい
test
CHANGED
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@@ -1,4 +1,22 @@
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1
1
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一応こんな感じでいけるかもしれません
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2
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+
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3
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+
- 元データ
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4
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+
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5
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```SQL
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6
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+
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7
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+
create table posts(id int,user_id int,created_at varchar(30));
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8
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9
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insert into posts values
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10
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+
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11
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(1,10,'2019-11-01T22:11:05.000+09:00'),
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12
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+
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13
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+
(2,10,'2019-11-02T22:11:05.000+09:00'),
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14
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15
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+
(3,20,'2019-11-01T22:11:05.000+09:00');
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16
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+
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17
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```
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18
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+
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19
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+
- 検索
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2
20
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3
21
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```SQL
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4
22
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