回答編集履歴
2
推敲
answer
CHANGED
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@@ -15,8 +15,8 @@
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15
15
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下記で、type_listにtypeが列挙され、それと同じ並びでtype毎の計が列挙されます。
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16
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```SQL
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17
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select date, sum(type_total) sub_total
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18
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-
, array_agg(type order by type)
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18
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+
, array_agg(type order by type) type_ary
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19
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-
, array_agg(type_total order by type)
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19
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, array_agg(type_total order by type) type_total_ary
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from (
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SELECT date, type, SUM(amount) AS type_total
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FROM table t1 left join type_table t2
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1
追記
answer
CHANGED
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@@ -8,4 +8,21 @@
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8
8
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FROM table t1 left join type_table t2
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on t1.type_id=t2.id
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GROUP BY date
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11
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-
```
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11
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+
```
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12
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+
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13
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+
追記
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14
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--
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15
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+
下記で、type_listにtypeが列挙され、それと同じ並びでtype毎の計が列挙されます。
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16
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+
```SQL
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17
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+
select date, sum(type_total) sub_total
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18
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+
, array_agg(type order by type) type_list
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19
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, array_agg(type_total order by type) type_total_list
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from (
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21
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SELECT date, type, SUM(amount) AS type_total
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FROM table t1 left join type_table t2
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on t1.type_id=t2.type_id
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24
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GROUP BY date, type
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) step1
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26
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group by date
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27
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```
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28
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後は受け取るプログラム側で、typeテーブルで列の数を決めて、該当する箇所に埋め込むようにします。
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