回答編集履歴
2
追記
answer
CHANGED
@@ -77,4 +77,23 @@
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77
77
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}
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78
78
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79
79
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console.log( hoge( 4 ) );
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80
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-
```
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80
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+
```
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81
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+
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82
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+
```Javascript
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83
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+
function hoge( n ) {
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84
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var ary = [];
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85
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var i, j, k, x = 1;
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86
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+
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87
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for ( i = 0; i < n; i ++ ) ary[ i ] = [];
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88
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+
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89
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+
for ( k = 0; k <= ( n - 1 ) * 2; k ++ )
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90
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+
for ( i = 0, j = k; j >= 0; i ++, j -- )
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91
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if ( i < n && j < n )
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92
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ary[ i ][ j ] = x ++;
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93
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+
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94
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return ary;
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95
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}
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96
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console.log( hoge( 4 ) );
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97
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+
```
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98
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+
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99
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+
最短で4行、これ以上無理
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1
追加
answer
CHANGED
@@ -40,4 +40,41 @@
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40
40
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console.log( hoge( 4 ) );
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41
41
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```
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42
42
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43
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-
あまりきれいなプログラムじゃありませんが
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43
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+
あまりきれいなプログラムじゃありませんが
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44
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+
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45
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+
```Javascript
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46
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+
function hoge ( n ) {
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47
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+
var ary = [];
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48
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var i;
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49
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+
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50
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for ( i = 0; i < n; i ++ ) {
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51
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ary[ i ] = [];
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52
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}
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53
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+
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54
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moga( ary, 0, 0, 1, 1, n );
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55
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+
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56
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function fuga( ary, i, j, x, y, n ) {
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57
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if ( y < 0 || j < 0 ) return;
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58
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+
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59
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+
if ( i < n && j < n ) {
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60
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ary[ i ][ j ] = x;
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61
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}
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62
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+
if ( i == 0 ) {
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63
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fuga( ary, i + 1, j - 1, x + 1, 0, n );
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64
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x += y;
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65
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if ( j < n - 2 ) {
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66
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y++;
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67
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} else if ( j > n - 2 ) {
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68
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y--;
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69
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}
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70
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fuga( ary, i, j + 1, x, y, n );
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71
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} else {
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72
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+
fuga( ary, i + 1, j - 1, x + 1, y, n );
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73
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+
}
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74
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}
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75
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+
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76
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+
return ary;
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77
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}
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78
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+
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79
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+
console.log( hoge( 4 ) );
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80
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+
```
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