回答編集履歴
2
配列の2つ目以降の要素が異なる場合にも正しくソートされるように修正
answer
CHANGED
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@@ -6,7 +6,7 @@
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6
6
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b = Counter([len(aa) for aa in a])
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7
7
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# print(b)
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8
8
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9
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-
result = sorted(a, key=lambda x : (b[len(x)], x
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9
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+
result = sorted(a, key=lambda x : (b[len(x)], x))
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10
10
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print(result)
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11
11
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```
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12
12
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1
dictに変換する必要なかったので除去
answer
CHANGED
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@@ -3,7 +3,7 @@
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3
3
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```python
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4
4
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from collections import Counter
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5
5
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a =[['a','b','c'],['d','e'],['f','g','h'],['d','e'],['i','j','k','l'],['m','n'],['o']]
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6
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-
b =
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6
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+
b = Counter([len(aa) for aa in a])
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7
7
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# print(b)
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8
8
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9
9
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result = sorted(a, key=lambda x : (b[len(x)], x[0]))
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