回答編集履歴
1
tuiki
answer
CHANGED
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@@ -22,4 +22,50 @@
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}
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);
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});
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```
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# 追記
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disabledが変更になることも考えるとclassで処理する方がよいですね
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29
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```javascript
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30
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<style>
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.has-disabled{
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background-Color:#dedede;
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color:#888;
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}
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.has-disabled:hover{
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background-Color:black;
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color:white;
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cursor:not-allowed;
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}
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</style>
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<script>
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$(function(){
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$('.btn-disabled').has(':checkbox:disabled').addClass('has-disabled');
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$('.change-disabled').on('click',function(){
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$(this).prev('.btn-disabled').toggleClass('has-disabled').find(':checkbox').prop('disabled',function(){return $(this).is(':not(:disabled)');});
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});
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});
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</script>
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<div class="btn-group-toggle" data-toggle="buttons">
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<label class="input-group-text btn btn-disabled">
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<input type="checkbox" class="single-checkbox" disabled>
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<span>テスト</span>
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</label>
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<input type="button" value="change" class="change-disabled">
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</div>
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<div class="btn-group-toggle" data-toggle="buttons">
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<label class="input-group-text btn btn-disabled">
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<input type="checkbox" class="single-checkbox" disabled>
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<span>テスト</span>
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</label>
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<input type="button" value="change" class="change-disabled">
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</div>
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<div class="btn-group-toggle" data-toggle="buttons">
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<label class="input-group-text btn btn-disabled">
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<input type="checkbox" class="single-checkbox" disabled>
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<span>テスト</span>
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</label>
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<input type="button" value="change" class="change-disabled">
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</div>
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```
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