回答編集履歴
3
修正
answer
CHANGED
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@@ -28,7 +28,7 @@
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28
28
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.Where(a => (string)a.Attribute("name") == "pan")
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29
29
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.First();
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30
30
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pan.Add(new XElement("substance", new XAttribute("name", "yeast")));
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31
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-
output_xml.Save(
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31
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+
output_xml.Save(output_xml_filename);
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32
32
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Console.WriteLine(output_xml);
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33
33
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Console.ReadKey();
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34
34
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}
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2
修正
answer
CHANGED
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@@ -28,6 +28,7 @@
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28
28
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.Where(a => (string)a.Attribute("name") == "pan")
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29
29
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.First();
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30
30
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pan.Add(new XElement("substance", new XAttribute("name", "yeast")));
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31
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+
output_xml.Save(output_xml__filename);
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31
32
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Console.WriteLine(output_xml);
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32
33
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Console.ReadKey();
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33
34
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}
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1
追記
answer
CHANGED
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@@ -1,1 +1,37 @@
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1
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-
`xml.Save(ファイル名)`
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1
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+
`xml.Save(ファイル名)`
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2
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+
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3
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+
# 追記
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4
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+
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5
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+
以下のコードは XMLFile1.xml を読み込み、pan の子要素として yeast を追加し、out.xml に書き込みます。
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6
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+
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7
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+
```C#
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8
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+
using System;
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9
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+
using System.IO;
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10
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+
using System.Linq;
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11
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+
using System.Xml.Linq;
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12
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+
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13
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+
namespace ConsoleApp1
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|
14
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+
{
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15
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+
class Program
|
|
16
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+
{
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17
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+
static void Main(string[] args)
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18
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+
{
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19
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+
string dir = AppDomain.CurrentDomain.BaseDirectory;
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20
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+
string xml_filename = Path.Combine(dir, "XMLFile1.xml");
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21
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+
string output_xml_filename = Path.Combine(dir, "out.xml");
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22
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+
var xml = XDocument.Load(xml_filename);
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23
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+
var output_xml = XDocument.Parse(xml.ToString());
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24
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+
var pan = output_xml
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25
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+
.Root
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26
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+
.Element("products")
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27
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+
.Elements("product")
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28
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+
.Where(a => (string)a.Attribute("name") == "pan")
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|
29
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+
.First();
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30
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+
pan.Add(new XElement("substance", new XAttribute("name", "yeast")));
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31
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+
Console.WriteLine(output_xml);
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32
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+
Console.ReadKey();
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33
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+
}
|
|
34
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+
}
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|
35
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+
}
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36
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+
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37
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+
```
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