回答編集履歴
2
d
answer
CHANGED
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@@ -35,4 +35,27 @@
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35
35
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# 0 [0, 0, 0]
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36
36
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# 1 [1, 1, 1, 1, 1]
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37
37
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# 0 [0, 0, 0, 0]
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38
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+
```
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39
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+
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40
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+
## 自前で書く場合
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41
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+
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42
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```python
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43
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lst = [0, 0, 0, 0, 1, 0, 0, 0, 1, 1, 1, 1, 1, 0, 0, 0, 0]
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44
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N = 3
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45
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46
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curr_value = lst[0]
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47
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cnt = 0
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48
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for i, value in enumerate(lst):
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49
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if value == curr_value:
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50
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# 前回と同じ値ならカウント +1
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51
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cnt += 1
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52
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else:
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53
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# 前回と異なる値ならカウントを0にする。
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54
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cnt = 0
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55
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curr_value = value
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56
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57
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if cnt == N and value == 1:
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58
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# N個連続 かつ 値が1の場合ループ終了
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59
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print(i - N)
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60
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break
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38
61
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```
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1
d
answer
CHANGED
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@@ -6,7 +6,7 @@
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6
6
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lst = [0, 0, 0, 0, 1, 0, 0, 0, 1, 1, 1, 1, 1, 0, 0, 0, 0]
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7
7
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N = 3 # 「N 個以上連続していたら」という条件の値
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8
8
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9
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-
i =
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9
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i = 0
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10
10
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for k, g in groupby(lst):
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11
11
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g = list(g) # list に変換
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12
12
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@@ -18,6 +18,10 @@
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18
18
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i += len(g)
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19
19
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```
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20
20
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21
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+
```output
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22
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8
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23
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```
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24
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+
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21
25
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[itertools.groupby](https://docs.python.org/ja/3/library/itertools.html#itertools.groupby) の使い方
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22
26
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23
27
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```python
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