回答編集履歴
2
補足
test
CHANGED
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@@ -65,3 +65,9 @@
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65
65
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beforeStr = beforeStr.replace(/\r\n|\n|\r/g, '<br>');
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66
66
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67
67
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```
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68
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+
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69
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+
質問文のコードのようにループで何回も置換せず、このように一回だけ置換すれば、
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70
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+
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71
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`<span><span>Cheese</span> Cake</span>`
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72
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+
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73
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みたいなことは起こりません。
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1
追記
test
CHANGED
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@@ -1,7 +1,67 @@
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1
1
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`Cheese Cake`が`<span><span>Cheese</span> Cake</span>`になるので良ければ、
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2
2
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3
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-
ループの前で、`array1 = array1.sort(
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3
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+
ループの前で、`array1 = array1.sort((a,b)=>b.toString().length-a.toString().length);`すればいいです。
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4
4
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5
5
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6
6
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7
7
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あと、単語の前後に、単語境界指定を入れて`/\bwhite\b/g` とかにした方が良いかと思います。さらに、名詞は`/\bapples?\b/g`のように複数形も考慮した方が良いかも。
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8
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+
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9
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+
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10
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+
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11
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もう少し改善すると、複数形をさておくと、
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12
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+
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13
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```JavaScript
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14
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+
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15
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let array1 = [
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16
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+
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17
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"white",
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18
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19
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"apple",
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20
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21
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"brown",
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22
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23
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"tomato",
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24
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"cheese",
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26
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27
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"Cheese",
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28
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29
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"Cheese Inc\.",
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30
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31
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/* 追加日 */
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32
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33
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"Cheese Cake",
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34
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35
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"blueberry",
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36
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37
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"blueberry pie",
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38
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39
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"brown 2",
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40
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41
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"yellow",
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42
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43
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"brown4",
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44
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45
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/* 追加日 */
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46
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47
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"cat",
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48
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49
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"compact",
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50
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51
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"water",
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52
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53
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"water server",
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54
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55
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"yellowR"
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56
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+
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57
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]
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58
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+
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59
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let regstr = "\b"+array1.sort((a,b)=>b.length-a.length).join("\b|\b")+"\b";
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60
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+
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61
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let beforeStr = document.querySelector('#before').value;
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62
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+
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63
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beforeStr = beforeStr.replace(new RegExp(regstr), '<span>$&</span>');
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64
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+
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65
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beforeStr = beforeStr.replace(/\r\n|\n|\r/g, '<br>');
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66
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+
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67
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+
```
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