回答編集履歴
3
maketransをシンプルに。
answer
CHANGED
@@ -33,7 +33,7 @@
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33
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```python
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text = "(1,3),(4,6),(7,53),(65,143)"
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36
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-
print(text.translate(str.maketrans(
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36
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print(text.translate(str.maketrans("(),", "\0\0\n")))
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```
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39
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```text
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2
後半戦
answer
CHANGED
@@ -1,28 +1,48 @@
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1
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# 前半戦
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2
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1
3
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* **特定の文字列**で分割
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2
4
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3
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-
```
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5
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```text
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4
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-
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6
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['', 'mploy', '', '']
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7
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```
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6
8
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7
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-
* 空文字を**特定の文字列**に戻す
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9
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* 空文字列を**特定の文字列**に戻す
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10
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9
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-
```
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11
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```text
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10
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-
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12
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['e', 'mploy', 'e', 'e']
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```
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* 改行で連結
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-
```
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```text
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-
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+
e
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-
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+
mploy
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-
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e
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-
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e
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```
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-
# 出来上がりはこちら
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24
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+
##### 出来上がりはこちら
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```python
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word = "employee"
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c = "e"
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print("\n".join([s if s else c for s in word.split(c)]))
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30
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```
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+
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# 後半戦
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33
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+
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34
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```python
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35
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text = "(1,3),(4,6),(7,53),(65,143)"
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print(text.translate(str.maketrans({"(":"", ")":"", ",":"\n"})))
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```
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```text
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1
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+
3
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4
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6
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+
7
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53
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65
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+
143
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48
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```
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1
列
answer
CHANGED
@@ -1,10 +1,10 @@
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1
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-
* **特定の文字**で分割
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1
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+
* **特定の文字列**で分割
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2
2
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3
3
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```python
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4
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# ['', 'mploy', '', '']
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5
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```
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6
6
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7
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-
* 空文字を**特定の文字**に戻す
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7
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+
* 空文字を**特定の文字列**に戻す
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8
8
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9
9
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```python
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10
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# ['e', 'mploy', 'e', 'e']
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