回答編集履歴
2
関数名が適当でないと思った。けどほかに良いのも思いつかなかった
answer
CHANGED
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@@ -38,7 +38,7 @@
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38
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[16,15,14,13],
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[9,10,0,12]]
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-
def
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def f(data):
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result = []
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for col in zip(*data):
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if sum(col) == 34:
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@@ -56,8 +56,8 @@
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return list(map(list, zip(*result)))
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print(
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print(f(data1))
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print(
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print(f(data2))
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""" =>
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[[8, 7, 6, 5], [1, 2, 3, 4], [16, 15, 14, 13], [9, 10, 11, 12]]
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63
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[[8, 7, 6, 5], [1, 2, 11, 4], [16, 15, 14, 13], [9, 10, 3, 12]]
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1
追記
answer
CHANGED
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@@ -22,4 +22,44 @@
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```
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zipでlistを転置する方法を利用しています。参考：
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[Python標準で転置行列](https://qiita.com/mas9612/items/821fbb4c881b7a836451)
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[Python標準で転置行列](https://qiita.com/mas9612/items/821fbb4c881b7a836451)
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### 追記
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28
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作ってみました。上のコードを多少書き換えただけ。ヘンなデータが入ってきたときのことはまったく考えていません。
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```python
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data1 = [[8,7,6,5],
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[1,0,3,4],
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33
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[16,15,14,13],
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34
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[9,10,0,12]]
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data2 = [[8,7,6,5],
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[1,2,0,4],
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[16,15,14,13],
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[9,10,0,12]]
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def fillz(data):
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result = []
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for col in zip(*data):
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if sum(col) == 34:
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result.append(col)
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else:
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if col.count(0) == 1:
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# 一列に0が1つのとき
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tmp = list(col)
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tmp[tmp.index(0)] = 34 - sum(col)
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result.append(tmp)
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else:
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# 一列に2つあるとき
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fillvals = [i for i in range(1, 17) if i not in sum(data, [])]
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result.append([fillvals.pop() if e == 0 else e for e in col])
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return list(map(list, zip(*result)))
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print(fillz(data1))
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print(fillz(data2))
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""" =>
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[[8, 7, 6, 5], [1, 2, 3, 4], [16, 15, 14, 13], [9, 10, 11, 12]]
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63
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[[8, 7, 6, 5], [1, 2, 11, 4], [16, 15, 14, 13], [9, 10, 3, 12]]
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64
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"""
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65
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```
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