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トップPython 3.xに関する質問多次元リストの一部の数値だけ変えたい

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2

修正

2018/06/01 12:09

投稿

LouiS0616
LouiS0616

スコア35660

test CHANGED
@@ -16,13 +16,17 @@
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  a = [[0, 0, 0], [0, 0, 0], [0, 0, 0]]
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- for e in a:
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+ a[1][1] = 1
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-
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- print(id(e))
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- print()
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+ for e in a:
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+
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+ print(f'{id(e)}: {e}')
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+
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+
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+
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+ print('-'*42)
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@@ -32,13 +36,17 @@
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  b = [[0] * 3] * 3
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+ b[1][1] = 1
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+
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+
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+
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  for e in b:
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- print(id(e))
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+ print(f'{id(e)}: {e}')
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- print()
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+ print('-'*42)
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@@ -48,38 +56,48 @@
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  c = [[0] * 3 for _ in range(3)]
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+ c[1][1] = 1
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+
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+
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+
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  for e in c:
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- print(id(e))
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+ print(f'{id(e)}: {e}')
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+
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+
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+
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+ print('-'*42)
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  ```
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- **実行結果** [Wandbox](https://wandbox.org/permlink/xdcNb06JtTjRN3AI)
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+ **実行結果** [Wandbox](https://wandbox.org/permlink/HEZpkk81o8qx6UYW)
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  ```
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- 139752138114696
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+ 139895659521672: [0, 0, 0]
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- 139752138114888
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+ 139895659521864: [0, 1, 0]
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- 139752138115208
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+ 139895659522184: [0, 0, 0]
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+ ------------------------------------------
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+ 139895659523656: [0, 1, 0]
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- 139752138115336
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+ 139895659523656: [0, 1, 0]
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- 139752138115336
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+ 139895659523656: [0, 1, 0]
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- 139752138115336
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+ ------------------------------------------
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+ 139895659523976: [0, 0, 0]
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+ 139895659524040: [0, 1, 0]
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- 139752138116296
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+ 139895659544648: [0, 0, 0]
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- 139752138116360
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+ ------------------------------------------
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-
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- 139752138116424
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  ```

1

追記

2018/06/01 12:09

投稿

LouiS0616
LouiS0616

スコア35660

test CHANGED
@@ -5,3 +5,81 @@
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  良く躓くポイントなので、調べれば同様の話題はたくさん出てきます。
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+
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+
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+
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+ ---
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+
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+ 実際にidを確認してみると良いです。
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+
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+ ```Python
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+
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+ a = [[0, 0, 0], [0, 0, 0], [0, 0, 0]]
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+
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+ for e in a:
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+
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+ print(id(e))
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+
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+
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+
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+ print()
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+
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+
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+
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+ #
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+
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+ #
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+
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+ b = [[0] * 3] * 3
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+
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+ for e in b:
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+
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+ print(id(e))
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+
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+
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+
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+ print()
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+
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+
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+
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+ #
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+
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+ #
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+
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+ c = [[0] * 3 for _ in range(3)]
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+
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+ for e in c:
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+
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+ print(id(e))
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+
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+ ```
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+
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+
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+
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+ **実行結果** [Wandbox](https://wandbox.org/permlink/xdcNb06JtTjRN3AI)
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+
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+ ```
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+
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+ 139752138114696
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+
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+ 139752138114888
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+
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+ 139752138115208
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+
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+
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+
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+ 139752138115336
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+
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+ 139752138115336
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+
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+ 139752138115336
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+
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+
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+
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+ 139752138116296
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+
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+ 139752138116360
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+
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+ 139752138116424
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+
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+ ```