回答編集履歴
2
追記
test
CHANGED
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@@ -2,7 +2,7 @@
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```Python
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arr = [["A","B","C"],["D","E","F"],["G","H","I"]]
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arr = [["A", "B", "C"], ["D", "E", "F"], ["G", "H", "I"]]
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@@ -10,9 +10,7 @@
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try:
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pos = (y, row.index("G"))
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pos = (y, x)
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break
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@@ -20,11 +18,31 @@
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pass
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-
else:
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-
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pos = None
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print(pos)
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```
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ちょっと捻った方法。
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30
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31
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```Python
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32
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from itertools import chain
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arr = [["A", "B", "C"], ["D", "E", "F"], ["G", "H", "I"]]
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pos = divmod(
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list(chain(*arr)).index("G"), len(arr[0])
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)
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print(pos)
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48
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1
追記
test
CHANGED
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@@ -1,3 +1,57 @@
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1
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素直な方法。
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2
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3
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```Python
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arr = [["A","B","C"],["D","E","F"],["G","H","I"]]
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for y, row in enumerate(arr):
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try:
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x = row.index("G")
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pos = (y, x)
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break
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except ValueError:
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pass
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else:
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pos = None
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print(pos)
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```
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内包表記を使った方法。
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```Python
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arr = [["A", "B", "C"], ["D", "E", "F"], ["G", "H", "I"]]
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pos = [
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(x, y) for y, row in enumerate(arr) for x, elem in enumerate(row) if arr[x][y] == "G"
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46
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][0]
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print(pos)
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```
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52
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54
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1
55
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NumPyを使うのもアリかもしれませんね。
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2
56
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3
57
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```Python
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@@ -14,6 +68,6 @@
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14
68
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15
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pos = tuple(nd[0] for nd in np.where(arr == "G"))
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17
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print(pos)
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71
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print(pos)
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73
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```
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