回答編集履歴
3
回答を質問に合わせて修正
test
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@@ -73,3 +73,85 @@
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#2018-01-03 850 625
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```
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---
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**【修正版】**
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> dictがリストに入っている場合
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```Python
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import pandas as pd
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df = pd.DataFrame({
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'Date':['2018/1/1','2018/1/2','2018/1/2','2018/1/3','2018/1/3'],
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'Status':[[{'Quantitiy':100, 'Price':1000}],
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[{'Quantitiy':10, 'Price':5000}],
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[{'Quantitiy':50, 'Price':1500}],
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[{'Quantitiy':500, 'Price':100}],
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[{'Quantitiy':125, 'Price':750}]]
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})
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df['Date'] = pd.to_datetime(df['Date'])
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print(df)
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# Date Status
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#0 2018-01-01 {'Quantitiy': 100, 'Price': 1000}
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#1 2018-01-02 {'Quantitiy': 10, 'Price': 5000}
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#2 2018-01-02 {'Quantitiy': 50, 'Price': 1500}
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#3 2018-01-03 {'Quantitiy': 500, 'Price': 100}
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#4 2018-01-03 {'Quantitiy': 125, 'Price': 750}
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125
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df = pd.concat([df, df['Status'].apply(lambda d: pd.Series(d[0]))], axis=1).drop('Status', axis=1)
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print(df)
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# Date Price Quantitiy
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#0 2018-01-01 1000 100
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#1 2018-01-02 5000 10
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#2 2018-01-02 1500 50
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#3 2018-01-03 100 500
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#4 2018-01-03 750 125
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print(df.groupby('Date').sum())
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# Price Quantitiy
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#Date
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#2018-01-01 1000 100
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#2018-01-02 6500 60
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#2018-01-03 850 625
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```
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2
回答の一部を追加
test
CHANGED
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@@ -58,4 +58,18 @@
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#4 2018-01-03 750 125
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print(df.groupby('Date').sum())
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# Price Quantitiy
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#Date
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#2018-01-01 1000 100
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#2018-01-02 6500 60
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#2018-01-03 850 625
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61
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```
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1
タイポ修正
test
CHANGED
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@@ -1,4 +1,4 @@
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1
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-
辞書データをColumnに展開してから処理するというのは駄目で
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辞書データをColumnに展開してから処理するというのは駄目でしょうか？
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