回答編集履歴
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文言の編集
test
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こんな感じでしょうか？否定グループ`[^否定対象]`を使う方法です。
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こんな感じでしょうか？否定グループ`[^否定対象]`を使う方法です。
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文言の編集
test
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こんな感じでしょうか？否定グループ`[^否定対象]`を使う方法です。(ここだと全角＠も半角になっちゃうんですね…)
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修正案
test
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@@ -1,59 +1,105 @@
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普通に`@`ごと取ってくればいいのではないでしょうか？(ここだと全角＠も半角になっちゃうんですね…)
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```python
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re.findall(r'[^@＠]+[@＠]',text)
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```
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実行例
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```python
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import re
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text1 = 'hogefuga@barbaz@'
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text2 = 'fizz@buzz＠'
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text3 = 'aaaa＠bbbb＠'
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for t in (text1,text2,text3):
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m = re.findall(r'[^@＠]+[@＠]',t)
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print(*m,sep='\n',end='\n\n')
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for n in m:
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if n[-1] == '@':
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print(n[:-1],'と半角@')
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elif n[-1] == '＠':
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print(n[:-1],'と全角＠')
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print('\n-----\n')
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```
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実行例の結果
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```plain
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hogefuga@
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barbaz@
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hogefuga と半角@
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barbaz と半角@
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-----
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~~bbbb~~
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fizz@
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buzz＠
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fizz と半角@
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buzz と全角＠
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-----
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aaaa＠
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bbbb＠
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aaaa と全角＠
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bbbb と全角＠
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-----
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```
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1
修正
test
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@@ -1,63 +1,59 @@
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こういうことがしたいのですかね？
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~~こういうことがしたいのですかね？~~
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~~python~~
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re.findall(r'([^@＠]+)[@＠]',text)
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~~re.findall(r'([^@＠]+)[@＠]',text)~~
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```
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実行例
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~~実行例~~
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~~python~~
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import re
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~~import re~~
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text1 = 'hogefuga@barbaz@'
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~~text1 = 'hogefuga@barbaz@'~~
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text2 = 'fizz@buzz＠'
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~~text2 = 'fizz@buzz＠'~~
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text3 = 'aaaa＠bbbb＠'
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~~text3 = 'aaaa＠bbbb＠'~~
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for t in (text1,text2,text3):
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~~for t in (text1,text2,text3):~~
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print(*re.findall(r'([^@＠]+)[@＠]',t),sep='\n',end='\n\n')
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~~ print(*re.findall(r'([^@＠]+)[@＠]',t),sep='\n',end='\n\n')~~
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```
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実行例の結果
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~~実行例の結果~~
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~~plain
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hogefuga
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~~hogefuga~~
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barbaz
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~~barbaz~~
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fizz
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~~fizz~~
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buzz
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~~buzz~~
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aaaa
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~~aaaa~~
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bbbb
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~~bbbb~~
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``
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`@`残すのでしたね。ごめんなさい修正案考えてます…(^ ^;
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