回答編集履歴
1
integer -> char
answer
CHANGED
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@@ -4,7 +4,7 @@
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4
4
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select
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5
5
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count(*) col1,
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6
6
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concat(1, 'a') col2,
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7
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-
concat(cast(count(*) as
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7
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+
concat(cast(count(*) as char), 'a') col3
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8
8
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from
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9
9
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dual
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10
10
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```
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