回答編集履歴
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抽出
test
CHANGED
@@ -11,3 +11,95 @@
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DEFをテーブルABそれぞれにDISTINCTで抽出してUNION ALLし
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group byしてhavingでcount(*)が1のデータを抽出するといいでしょう
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# sample
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```SQL
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create table tbl_a(id int unique ,D int,E int, F int, G varchar(10));
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insert into tbl_a values(1,100,100,100,'aaa'),(2,200,200,200,'bbb'),(3,100,200,100,'ccc'),(4,100,100,100,'ddd');
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create table tbl_b(id int unique ,D int,E int, F int, H varchar(10));
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insert into tbl_b values(101,100,100,100,'eee'),(102,200,100,200,'fff'),(103,200,200,200,'ggg'),(104,200,100,200,'hhh');
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```
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- 片方にしかないDEF
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```SQL
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select D,E,F from(
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select distinct D,E,F from tbl_a
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union all select distinct D,E,F from tbl_b
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) as sub
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group by D,E,F
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having count(*)=1
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```
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- それぞれ合致するデータを抽出
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```SQL
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/* tbl_a */
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select * from tbl_a
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where (D,E,F) in (
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select D,E,F from(
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select distinct D,E,F from tbl_a
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union all select distinct D,E,F from tbl_b
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) as sub
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group by D,E,F
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having count(*)=1
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);
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/* tbl_b */
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select * from tbl_b
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where (D,E,F) in (
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select D,E,F from(
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select distinct D,E,F from tbl_a
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union all select distinct D,E,F from tbl_b
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) as sub
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group by D,E,F
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having count(*)=1
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);
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```
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※注意:命題の追記をみるかぎり、tbl_aとtbl_bは構成が違うようなので
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一発でデータ抽出はできません。二度にわけて処理して下さい
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