回答編集履歴
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test
CHANGED
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@@ -53,3 +53,51 @@
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[sum(winner_records==1)/n , sum(winner_records==2)/n]
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追加：
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60
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61
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引き分けも勝負回数に含める場合はfor を使います。
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62
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n=1000;%勝負回数
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n_sai_1 = 4;%player1のサイコロ数
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n_sai_2 = 1;
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player_1_records =[];%player1の出目記録用
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player_2_records =[];
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winner_records = [];%勝敗：１ならplayer1の勝利、2ならplayer2の勝利
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for i=1:n
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player_1_result=randi(6,1,n_sai_1);%１から６までの自然するからランダムにn_sai_1個選ぶ
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80
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player_2_result=randi(6,1,n_sai_2);
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if max(player_1_result) == max(player_2_result) %引き分けなら再勝負
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result = 0
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else
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result = 1+ (max(player_1_result) < max(player_2_result));
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end
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player_1_records=[player_1_records;player_1_result];
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player_2_records=[player_2_records;player_2_result];
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winner_records = [winner_records; result];
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end
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103
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[sum(winner_records==1)/n , sum(winner_records==2)/n, sum(winner_records==0)/n]
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