回答編集履歴
4
Calendarのまま判定する方法
test
CHANGED
@@ -135,3 +135,55 @@
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}
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```
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今更追加(17/09/17)。
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- 日付比較するメソッドを作る
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```java
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public boolean getFlg() throws ParseException {
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SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd");
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Date startDate = sdf.parse("2007-01-01");
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Date endDate = sdf.parse("2017-05-26");
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Calendar from = Calendar.getInstance(),
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today = Calendar.getInstance(),
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to = Calendar.getInstance();
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from.setTime(startDate);
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to.setTime(endDate);
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return compareByDate(from, today) <= 0 && compareByDate(today, to) <= 0;
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}
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public static int compareByDate(Calendar c1, Calendar c2) {
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int i = Integer.compare(c1.get(Calendar.YEAR), c2.get(Calendar.YEAR));
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if (i != 0) return i;
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return Integer.compare(c1.get(Calendar.DAY_OF_YEAR), c2.get(Calendar.DAY_OF_YEAR));
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}
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```
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3
修正
test
CHANGED
@@ -38,7 +38,7 @@
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-
return diff1 >= 0 && diff2 >
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return diff1 >= 0 && diff2 > 0;
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}
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@@ -64,7 +64,7 @@
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-
return startDate <= now && now <
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return startDate <= now && now < endDate;
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}
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2
現在時刻関係のDateの処理が意味なかったので削除
test
CHANGED
@@ -16,8 +16,6 @@
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Date endDate = sdf.parse("2017-05-26");
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-
Date now = new Date();
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-
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Calendar from = Calendar.getInstance(),
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@@ -27,8 +25,6 @@
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to = Calendar.getInstance();
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from.setTime(startDate);
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-
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today.setTime(now);
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to.setTime(endDate);
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1
不要な例外宣言を削除、方法をもう一つ追加\(long値比較\)
test
CHANGED
@@ -48,13 +48,43 @@
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```
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- getTime()で得られるlong値で比較。その際に終了日時のほうに1日相当のミリ秒を加算する
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```java
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public boolean getFlg() throws ParseException {
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SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd");
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long startDate = sdf.parse("2007-01-01").getTime();
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long endDate = sdf.parse("2017-05-26").getTime() + 24L * 60L * 60L * 1000L;
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long now = new Date().getTime();
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return startDate <= now && now <= endDate;
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}
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```
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- 逆転の発想。文字列に変換して比較する
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日付の後先と文字列化した日付の後先は一致する
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```java
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-
public boolean getFlg()
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public boolean getFlg() {
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@@ -86,7 +116,7 @@
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```java
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-
public boolean getFlg()
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+
public boolean getFlg() {
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