回答編集履歴
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回答を追記
test
CHANGED
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@@ -15,3 +15,81 @@
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ds.Relations.Add("NewTable", AAA.Columns("No"), BBB.Columns("No"))
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```
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-追記-
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ただ結果のDataTableが欲しいだけなら
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前提が
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```
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Dim AAA As New DataTable
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Dim BBB As New DataTable
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Dim newtable As New DataTable
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AAA.Columns.Add("No")
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AAA.Columns.Add("Value")
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AAA.Rows.Add(1, "a")
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AAA.Rows.Add(2, "b")
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AAA.Rows.Add(3, "c")
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BBB.Columns.Add("No")
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BBB.Columns.Add("Value")
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BBB.Rows.Add(1, "A")
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BBB.Rows.Add(2, "B")
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BBB.Rows.Add(3, "C")
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newtable.Columns.Add("No")
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newtable.Columns.Add("Value1")
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newtable.Columns.Add("Value2")
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```
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みたいなのだと思いますが
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```
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Dim joinresult = AAA.AsEnumerable.Select(Function(x) New With {
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.No = x.Item("No"),
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.Value1 = x.Item("Value"),
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.Value2 = BBB.AsEnumerable.Where(Function(y) y.Item("No") = x.Item("No")).FirstOrDefault?.Item("Value")
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})
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For Each item In joinresult.ToList
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newtable.Rows.Add(item.No, item.Value1, item.Value2)
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Next
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```
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みたいにしてもいいかもしれません
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