質問編集履歴
8
校正
title
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@@ -16,46 +16,6 @@
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全頂点をめぐる回路・全域木の最小の経路・全域木をもとめる
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期待したい流れ
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-
↓
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seekMin()
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leng[0][3] 1
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-
min = leng[x][y];
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xx = x;
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-
yy = y;
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-
reach[xx] = 0;
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-
reach[yy] = leng[x][y];
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-
reach[3] = 1;
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-
x = yy;
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y = xx continue;
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leng[3][0]スキップ
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leng[3][2] 1
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xx = x;
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yy = y;
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reach[yy] = leng[x][y];
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reach[2] = 1;
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x = yy;
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y = xx continue;
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leng[2][3]スキップ
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leng[2][4] 1
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xx = x;
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yy = y;
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reach[yy] = leng[x][y];
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reach[4] = 1;
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-
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-
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-
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-
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total = 0;
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for(int i = 0; i < n; i++)
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total += reach[i];
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-
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↑
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この流れを変数を利用して記述したいです。
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アルゴリズム書き直しでもよいです。
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-
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-
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###発生している問題・エラーメッセージ
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この辺りの処理の流れがわかりません
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7
思考中
title
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body
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@@ -18,59 +18,35 @@
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期待したい流れ
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↓
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-
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seekMin()
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min = MAX_VALUE;
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-
leng[0][3]
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leng[0][3] 1
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min = leng[x][y];
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xx = x;
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yy = y;
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reach[
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reach[xx] = 0;
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reach[yy] = leng[x][y];
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reach[3] = 1;
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min()
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x = yy;
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min = MAX_VALUE;
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y = xx continue;
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-
leng[3][0]
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leng[3][0]スキップ
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leng[3][
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leng[3][2] 1
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min = leng[x][y];
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xx = x;
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yy = y;
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reach[yy] = min;
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reach[1] = 1;
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min()
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x = yy;
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min = MAX_VALUE;
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y = xx continue;
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leng[1][0] 2;
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-
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reach[yy] = leng[x][y];
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xx = x;
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yy = y;
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reach[yy] = min;
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reach[0] = 2;
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-
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どうやって下につなぐか?
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ここの下へつなげる
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min2()
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min = MAX_VALUE;
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leng[4][2] 1;
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min = length[x][y];
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xx = x;
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yy = y;
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reach[yy] = min2;
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reach[2] = 1;
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min2()
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x = yy;
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min = MAX_VALUE;
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y = xx continue;
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leng[2][3]スキップ
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leng[2][
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leng[2][4] 1
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min2 = leng[x][y];
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xx = x;
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yy = y;
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for(int i = 0; i < reach.length; i++)
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reach[yy] = leng[x][y];
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reach[
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reach[4] = 1;
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total = 0;
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for(int i = 0; i < n; i++)
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total += reach[i];
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6
思考中
title
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File without changes
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body
CHANGED
@@ -51,9 +51,9 @@
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どうやって下につなぐか?
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ここの下へつなげる
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min2()
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-
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min = MAX_VALUE;
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leng[4][2] 1;
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-
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min = length[x][y];
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xx = x;
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yy = y;
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reach[yy] = min2;
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5
思考中
title
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File without changes
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body
CHANGED
@@ -66,7 +66,8 @@
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min2 = leng[x][y];
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xx = x;
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yy = y;
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for(int i = 0; i < reach.length; i++)
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-
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if(reach[i] == -1)
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reach[3] != -1;終了
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4
思考中
title
CHANGED
File without changes
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body
CHANGED
@@ -18,23 +18,58 @@
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期待したい流れ
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↓
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-
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+
min()
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min = MAX_VALUE;
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leng[0][3] 1;
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min = leng[x][y];
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xx = x;
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yy = y;
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reach[
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reach[yy] = min;
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reach[3] = 1;
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min()
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x = yy;
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min = MAX_VALUE;
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y = xx continue;
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leng[3][0]をスキップして、
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leng[3][1] 1;
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min = leng[x][y];
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xx = x;
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yy = y;
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reach[yy] = min;
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reach[1] = 1;
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min()
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x = yy;
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min = MAX_VALUE;
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y = xx continue;
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leng[1][0] 2;
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min = leng[x][y];
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xx = x;
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yy = y;
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reach[yy] = min;
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reach[0] = 2;
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どうやって下につなぐか?
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ここの下へつなげる
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53
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+
min2()
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min2 = MAX_VALUE;
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leng[4][2] 1;
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min2 = length[x][y];
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xx = x;
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yy = y;
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reach[yy] = min2;
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reach[2] = 1;
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min2()
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x = yy;
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min = MAX_VALUE;
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y = xx continue;
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leng[2][3] 1;
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min2 = leng[x][y];
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xx = x;
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yy = y;
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while(reach[yy] != -1)
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reach[3] != -1;終了
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+
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total = 0;
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for(int i = 0; i < n; i++)
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total += reach[i];
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3
思考中
title
CHANGED
File without changes
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body
CHANGED
@@ -19,7 +19,7 @@
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19
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期待したい流れ
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20
20
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↓
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21
21
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22
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-
leng[0][3] 1
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22
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+
leng[0][3] 1;
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reach[0] = 0;
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reach[3] = 1;
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leng[3][0]をスキップして、
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@@ -33,7 +33,7 @@
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leng[4][2] 1;
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reach[2] = 1;
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leng[2][3] 1;
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36
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-
reach[3] = 1
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+
reach[3] != -1;終了
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total = 0;
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for(int i = 0; i < n; i++)
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2
思考中
title
CHANGED
File without changes
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body
CHANGED
@@ -28,6 +28,7 @@
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28
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leng[1][0] 2;
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reach[0] = 2;
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30
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31
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+
どうやって下につなぐか?
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31
32
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ここの下へつなげる
|
32
33
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leng[4][2] 1;
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33
34
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reach[2] = 1;
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@@ -39,7 +40,10 @@
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39
40
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total += reach[i];
|
40
41
|
|
41
42
|
↑
|
43
|
+
この流れを変数を利用して記述したいです。
|
44
|
+
アルゴリズム書き直しでもよいです。
|
42
45
|
|
46
|
+
|
43
47
|
###発生している問題・エラーメッセージ
|
44
48
|
|
45
49
|
この辺りの処理の流れがわかりません
|
1
思考中
title
CHANGED
File without changes
|
body
CHANGED
@@ -16,7 +16,30 @@
|
|
16
16
|
|
17
17
|
全頂点をめぐる回路・全域木の最小の経路・全域木をもとめる
|
18
18
|
|
19
|
+
期待したい流れ
|
20
|
+
↓
|
19
21
|
|
22
|
+
leng[0][3] 1
|
23
|
+
reach[0] = 0;
|
24
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+
reach[3] = 1;
|
25
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+
leng[3][0]をスキップして、
|
26
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+
leng[3][1] 1;
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27
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+
reach[1] = 1;
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28
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+
leng[1][0] 2;
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29
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+
reach[0] = 2;
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30
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+
|
31
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+
ここの下へつなげる
|
32
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+
leng[4][2] 1;
|
33
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+
reach[2] = 1;
|
34
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+
leng[2][3] 1;
|
35
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+
reach[3] = 1;
|
36
|
+
|
37
|
+
total = 0;
|
38
|
+
for(int i = 0; i < n; i++)
|
39
|
+
total += reach[i];
|
40
|
+
|
41
|
+
↑
|
42
|
+
|
20
43
|
###発生している問題・エラーメッセージ
|
21
44
|
|
22
45
|
この辺りの処理の流れがわかりません
|