質問編集履歴

1

付けたし

2016/05/13 02:53

投稿

kisaragizinzin7
kisaragizinzin7

スコア90

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  このx軸y軸に回転する方法を教えていただきたいです。
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  よろしくお願いします。
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+ 追記
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+ 原点対象のプログラムを載せておきます
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+ ```ここに言語を入力
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+
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+ コード
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+ public class MainActivity extends Activity implements Runnable{
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+ Handler handler = new Handler();
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+ Thread thread;
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+ CanvasView canvasview;
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+ Cherry cherry;
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+ @Override
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+ protected void onCreate(Bundle savedInstanceState) {
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+ super.onCreate(savedInstanceState);
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+ canvasview = new CanvasView(this);
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+ setContentView(canvasview);
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+ cherry = new Cherry();
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+ canvasview.getCherry(cherry);
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+ cherry.start();
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+ thread = new Thread(this);
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+ thread.start();
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+ }
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+ public void run(){
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+ handler.post(new Runnable() {
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+ @Override
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+ public void run(){
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+ canvasview.invalidate();
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+ handler.postDelayed(this, 1);
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+ }
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+ });
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+ }
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+ }
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+ ```
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+ ```ここに言語を入力
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+ コード
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+ public class CanvasView extends View{
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+ Cherry cherry;
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+ public CanvasView(Context context) {
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+ super(context);
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+ }
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+ public void getCherry(Cherry cherry){
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+ this.cherry = cherry;
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+ }
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+
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+ @Override
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+ public void onDraw(Canvas canvas){
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+ canvas.translate(1000, 200);
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+ canvas.rotate(cherry.angle);
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+ canvas.drawRect(-50, -100, 50, 100, cherry.paint);
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+ }
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+ ```
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+ ```ここに言語を入力
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+ コード
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+ public class Cherry extends Thread{
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+ Paint paint = new Paint();
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+ Path path = new Path();
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+ int angle = 0;
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+ public void run(){
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+ paint.setColor(Color.MAGENTA);
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+ paint.setStyle(Paint.Style.FILL);
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+ for(int i = 0; i < 360; i++){
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+ try{
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+ Thread.sleep(5);
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+ }
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+ catch(InterruptedException e){
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+ }
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+ angle = angle + 1;
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+ }
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+ }
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+ }
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+ ```