質問編集履歴
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質問を明確にしました。
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通信時にタイムアウトエラー発生
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##やろうとしていること
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MQTTメッセージを受信(Subscribe)し、
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受信メッセージに応じた処理を行う。
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②の処理が実行されると、プログラムが終了してしまいます。(スイッチを押す前にプログラムが終了してしまいます。)
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終了したときに表示されるエラー情報を↓に添付しますが、
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このエラーの内容、なぜこのエラーが起こるのかが分かりません。
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##プログラム（Subscribe)
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```python
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#!/usr/bin/python
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# coding: utf-8
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import time
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from AWSIoTPythonSDK.MQTTLib import AWSIoTMQTTClient
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import subprocess
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CLIENT_ID = "AWS"
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ENDPOINT = "hoge.amazonaws.com" # <random>.iot.<region>.amazonaws.com
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PORT = 8883
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ROOT_CA = "/home/pi/dev/aws/rootCA.pem"
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PRIVATE_KEY = "/home/pi/dev/aws/hogee.pem.key"
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CERTIFICATE = "/home/pi/dev/aws/hoge.pem.crt"
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TOPIC = "test"
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client = AWSIoTMQTTClient(CLIENT_ID)
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client.configureEndpoint(ENDPOINT, PORT)
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client.configureCredentials(ROOT_CA, PRIVATE_KEY, CERTIFICATE)
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# AWSIoTMQTTClient connection configuration
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client.configureAutoReconnectBackoffTime(1, 32, 20)
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# -1:infinite
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client.configureOfflinePublishQueueing(-1)
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# Draining: 2 Hz
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client.configureDrainingFrequency(2)
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# 10 sec
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client.configureConnectDisconnectTimeout(10)
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# 5 sec
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client.configureMQTTOperationTimeout(5)
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def mycallback(client, userdata, message):
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print("Received message '" + str(message.payload) + "' on topic '" + message.topic + "' with QoS " + str(message.qos))
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if message.payload == "rrr":
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print("rrr")
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subprocess.check_call(['python','/home/pi/dev/rrr.py'])
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elif message.payload == "xxxx":
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print("xxxx")
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subprocess.check_call(['python','/home/pi/dev/xxxx.py'])
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if __name__ == "__main__":
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try:
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client.connect()
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while True:
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client.subscribe(TOPIC, 1, mycallback)
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time.sleep(1)
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except KeyboardInterrupt:
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GPIO.cleanup()
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```
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##プログラム（実行するとエラーになってしまうコード)
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```python
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if __name__ == '__main__':
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try:
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# Setup leds
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setup(LED1, LED2, LED3, LED4)
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print("Received xxxx ...")
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# Run blinking forever
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while True:
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sw_state = GPIO.input(SW)
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if sw_state == True:
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blink(LED1, LED2, LED3, LED4)
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buzzer()
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else:
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GPIO.cleanup()
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break
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except KeyboardInterrupt:
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GPIO.cleanup()
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```
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##エラー
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