質問編集履歴
2
文法の修正
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@@ -32,7 +32,7 @@
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' 置換行列Pが存在すれば、Pありと出力
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If SubgraphHomotyping(A1, A2) = True Then
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Debug.Print "Pあり"
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-
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Else
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Debug.Print "Pなし"
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End If
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End Sub
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If Pが存在する Then
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SubgraphHomotyping = True
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Else
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SubgraphHomotyping = False
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End If
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1
ソースコードにおける変数A1, A2の初期化のエラーの改定
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@@ -20,31 +20,34 @@
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### 該当のソースコード
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```VBA
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Option Explicit
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Sub main()
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-
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Dim A1
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-
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Dim A2
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-
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A1 = [{0,1,1,1,1,0,0,0,0,0,0;1,0,0,0,0,1,0,0,0,0,0;1,0,0,0,0,0,1,1,1,0,0;1,0,0,0,0,0,0,0,0,0,0;1,0,0,0,0,0,0,0,0,0,0;0,1,0,0,0,0,0,0,0,2,1;0,0,1,0,0,0,0,0,0,0,0;0,0,1,0,0,0,0,0,0,0,0;0,0,1,0,0,0,0,0,0,0,0;0,0,0,0,0,2,0,0,0,0,0;0,0,0,0,0,1,0,0,0,0,0}]
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A2 = [{0,1,0,0,0;1,0,1,0,0;0,1,0,2,1;0,0,2,0,0;0,0,1,0,0}]
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-
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' 置換行列Pが存在すれば、Pありと出力
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-
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If SubgraphHomotyping(A1, A2) = True Then
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-
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Debug.Print "Pあり"
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-
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ElseIf SubgraphHomotyping(A1, A2) = False Then
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-
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Debug.Print "Pなし"
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-
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End If
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End Sub
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' 置換行列Pが存在するか判定する処理(存在すればTrue, 存在しなければFalse)
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Function SubgraphHomotyping(A1
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Function SubgraphHomotyping(A1 As Variant, A2 As Variant) As Boolean
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-
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-
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' 処理をここに記述
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-
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If Pが存在する Then
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SubgraphHomotyping = True
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-
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ElseIf Pが存在しない Then
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-
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SubgraphHomotyping = False
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-
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End If
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-
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End Function
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```
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