awkの出力がうまくいきません

下のコードを実際に動した時に
203100B
203101K
.
.
.
となって欲しいのですが全部最後に付く文字がAになってしまいます。
どこがおかしいのか教えていただけますでしょうか。

#!/usr/bin/awk -f
BEGIN{

for(i = 0;i <= 40; i++){
zyu[i]=int(i/10)
iti[i]=i%10
check[i]=((33+zyu[i]*3+iti[i]*2)%11)%10
if (check[i]=0) printf("2031%02d%1s\n",i,"B")
else if (check[i]=1) printf("2031%02d%1s\n",i,"A")
else if (check[i]=2) printf("2031%02d%1s\n",i,"K")
else if (check[i]=3) printf("2031%02d%1s\n",i,"J")
else if (check[i]=4) printf("2031%02d%1s\n",i,"H")
else if (check[i]=5) printf("2031%02d%1s\n",i,"G")
else if (check[i]=6) printf("2031%02d%1s\n",i,"F")
else if (check[i]=7) printf("2031%02d%1s\n",i,"E")
else if (check[i]=8) printf("2031%02d%1s\n",i,"D")
else if (check[i]=9) printf("2031%02d%1s\n",i,"C")
}
}

行動規範の内容に同意します

回答1件

if 文における同値の判定では = ではなく == を使います。

awk
1#!/usr/bin/awk -f
2
3BEGIN{
4for(i = 0;i <= 40; i++){
5  zyu[i]=int(i/10)
6  iti[i]=i%10
7  check[i]=((33+zyu[i]*3+iti[i]*2)%11)%10
8  if (check[i]==0) printf("2031%02d%1s\n",i,"B")
9    else if (check[i]==1) printf("2031%02d%1s\n",i,"A")
10    else if (check[i]==2) printf("2031%02d%1s\n",i,"K")
11    else if (check[i]==3) printf("2031%02d%1s\n",i,"J")
12    else if (check[i]==4) printf("2031%02d%1s\n",i,"H")
13    else if (check[i]==5) printf("2031%02d%1s\n",i,"G")
14    else if (check[i]==6) printf("2031%02d%1s\n",i,"F")
15    else if (check[i]==7) printf("2031%02d%1s\n",i,"E")
16    else if (check[i]==8) printf("2031%02d%1s\n",i,"D")
17    else if (check[i]==9) printf("2031%02d%1s\n",i,"C")
18  }
19}