for in文

Question

for in文を使って、指定した回数だけ回しながらfor in文の中で配列の中身を使いたいのですがどういう実装をすれば良いのでしょうか？

let items = ["fa","ce","bo","ok"]

for item in 1...3 {

}

やりたいこととしてはこのitemにitemsの要素を順番に入れつつ、指定した回数回すことです。

Answer 1

やり方はいろいろあると思います、以下を参考にしてみてください。
環境: Xcode7.3.1, swift2.2

★ for - in

let items = ["fa","ce","bo","ok"]

for item in items {
    print("item =", item)
}

/*
 item = fa
 item = ce
 item = bo
 item = ok
*/

let items = ["fa","ce","bo","ok"]

for item in items.enumerate() {
    print("index = \(item.0), value = \(item.1)")
}

/*
 index = 0, value = fa
 index = 1, value = ce
 index = 2, value = bo
 index = 3, value = ok
*/

let items = ["fa","ce","bo","ok"]

for (index, value) in items.enumerate() {
    print("index = \(index), value = \(value)")
}

/*
 index = 0, value = fa
 index = 1, value = ce
 index = 2, value = bo
 index = 3, value = ok
*/

let items = ["fa","ce","bo","ok"]

for i in 0..<items.count {
    print("item =", items[i])
}

/*
 item = fa
 item = ce
 item = bo
 item = ok
*/

★ forEach

let items = ["fa","ce","bo","ok"]

items.forEach { (item) in
    print("item =", item)
}

/*
 item = fa
 item = ce
 item = bo
 item = ok
*/

let items = ["fa","ce","bo","ok"]

items.enumerate().forEach { (item) in
    print("index = \(item.0), value = \(item.1)")
}

/*
 index = 0, value = fa
 index = 1, value = ce
 index = 2, value = bo
 index = 3, value = ok
*/

Comments

[tosi_1211]

for item in items.enumerate() {
print("index = \(item.0), value = \(item.1)")
}

こんな構文あるんですね！とても助かります。