Spring Bootが起動できない

お世話になります。
Spring boot起動時に以下のエラーが発生します。
EntityクラスとRepositoryクラスが１つずつの場合は起動できますが
EntityクラスとRepositoryクラスを複数追加すると起動できません。
なぜでしょうか。
どなたかご教授願います。


Error starting ApplicationContext. To display the conditions report re-run your application with 'debug' enabled.
2022-02-17 12:44:55.731 ERROR 8783 --- [           main] o.s.boot.SpringApplication               : Application run failed

org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'vtnRepository' defined in com.example.demo.repository.VtnRepository defined in @EnableJpaRepositories declared on JpaRepositoriesRegistrar.EnableJpaRepositoriesConfiguration: Cannot resolve reference to bean 'jpaMappingContext' while setting bean property 'mappingContext'; nested exception is org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'jpaMappingContext': Invocation of init method failed; nested exception is javax.persistence.PersistenceException: [PersistenceUnit: default] Unable to build Hibernate SessionFactory; nested exception is org.hibernate.MappingException: Could not determine type for: java.util.Map, at table: asset, for columns: [org.hibernate.mapping.Column(reports)]
--省略--

package com.example.demo.entity;

import com.example.demo.openadr2.transport.OadrObject;
import lombok.Data;

import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.Table;

@Entity
@Data
@Table(name = "sample_targetvtn")
public class VtnEntity {
    @Id
    @Column(name = "vtn_id")
    private String vtnID;                                                                   //  VTN ID

    @Column(name = "vtn_name")
    private String vtnName;                                                                 //  VTN名
--省略--
}

package com.example.demo.entity;

import com.enernoc.open.oadr2.model.v20b.OadrTransportType;
import com.example.demo.openadr2.transport.OadrObject;
import lombok.Data;

import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.Table;

@Entity
@Data
@Table(name = "sample_sourceven")
public class VenEntity {
    @Id
    @Column(name = "ven_id")
    private String venID;                                                                   //  VEN ID

    @Column(name = "ven_name")
    private String venName;                                                                 //  VEN Name
--省略--
}

package com.example.demo.repository;

import com.example.demo.entity.VtnEntity;
import org.springframework.data.jpa.repository.JpaRepository;
import org.springframework.stereotype.Repository;

/**
 * VTN情報 Repository
 */
@Repository
public interface VtnRepository extends JpaRepository<VtnEntity, String> {

}

package com.example.demo.repository;

import com.example.demo.entity.VenEntity;
import org.springframework.data.jpa.repository.JpaRepository;
import org.springframework.stereotype.Repository;

/**
 * VEN情報 Repository
 */
@Repository
public interface VenRepository extends JpaRepository<VenEntity, String> {

}

package com.example.demo;

import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;
import org.springframework.boot.autoconfigure.domain.EntityScan;
import org.springframework.data.jpa.repository.config.EnableJpaRepositories;

@SpringBootApplication
public class DemoApplication {

    public static void main(String[] args) {
        SpringApplication.run(DemoApplication.class, args);
    }

}