error: overloaded function with no contextual type informationの解決方法がわからない

発生している問題・エラーメッセージ

easy/sense_of_distance.cpp: In function ‘int main()’:
easy/sense_of_distance.cpp:17:78: error: overloaded function with no contextual type information
   for (int i = 0; i < n; ++i) std::cout << a_1[i] << (i==(n-1) ? std::endl : ' ');
                                                                              ^~~
easy/sense_of_distance.cpp:18:78: error: overloaded function with no contextual type information
   for (int i = 0; i < n; ++i) std::cout << a_2[i] << (i==(n-1) ? std::endl : ' ');
                                                                              ^~~
easy/sense_of_distance.cpp:23:79: error: overloaded function with no contextual type information
   for (int i = 0; i < n; ++i) std::cout << dist[i] << (i==(n-1) ? std::endl : ' ');

該当のソースコード

C++
1int main() {
2  int n; std::cin >> n;
3
4  int* a_1 = new int[n]; // 
5  int* a_2 = new int[n];
6  for (int i = 0; i < n; ++i) {
7    int a; std::cin >> a;
8    a_1[a-1] = (n-1) - i;
9  }
10  for (int i = 0; i < n; ++i) {
11    int a; std::cin >> a;
12    a_2[a-1] = i;
13  }
14
15  for (int i = 0; i < n; ++i) std::cout << a_1[i] << (i==(n-1) ? std::endl : ' ');
16  for (int i = 0; i < n; ++i) std::cout << a_2[i] << (i==(n-1) ? std::endl : ' ');
17
18
19  int* dist = new int[n];
20  for (int i = 0; i < n; ++i) dist[i] = a_1[i] + a_2[i];
21  for (int i = 0; i < n; ++i) std::cout << dist[i] << (i==(n-1) ? std::endl : ' ');
22
23
24  // イモス法で答えを求める
25  int* ans = new int[2*n-1];
26  for (int i = 0; i < 2*n-1; ++i) ans[i] = 0;
27  for (int i = 0; i < n; ++i) ans[dist[i]] = 1;
28  for (int i = 1; i < 2*n-1; ++i) ans[i] = ans[i-1] + ans[i];
29  for (int i = 0; i < 2*n-1; ++i) std::cout << ans[i] << std::endl;
30
31
32  delete[] a_1;
33  delete[] a_2;
34  delete[] dist;
35  delete[] ans;
36}