回答編集履歴
3
USP
test
CHANGED
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@@ -20,3 +20,25 @@
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20
20
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```
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21
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きょうび、fetchで送るほうが楽だとおもいます。
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22
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fetchの場合データはformDataで格納すればエンコードも必要ありません
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23
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+
# 参考
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参考までにUSP版も
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25
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```javascript
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const req = new XMLHttpRequest();
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const data={
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grant_type:'authorization_code',
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redirect_uri:'sampleURI',
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code:'sampleCode',
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code_verifier:'sampleVerifierテスト',
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};
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const postData = Object.entries(data).reduce((x,y)=>(x.append(y[0],y[1]),x),new URLSearchParams());
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req.open('POST',restAPIURL);
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req.responseType = 'json';
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req.setRequestHeader("Accept","application/json");
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req.setRequestHeader("cache-control","no-cache");
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req.setRequestHeader("Content-Type","application/x-www-form-urlencoded");
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req.onload = function() {
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console.log(this.response);
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};
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console.log(postData);
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req.send(postData);
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```
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2
調整
test
CHANGED
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@@ -1,5 +1,4 @@
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1
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-
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1
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+
調整版
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2
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-
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3
2
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```javascript
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4
3
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const req = new XMLHttpRequest();
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5
4
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const data={
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1
調整
test
CHANGED
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@@ -1,13 +1,23 @@
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1
1
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XHRでPOSTするならarraybufferを指定してください
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2
2
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3
3
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```javascript
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4
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-
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4
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const req = new XMLHttpRequest();
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5
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const data={
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5
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-
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grant_type:'authorization_code',
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6
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-
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redirect_uri:'sampleURI',
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7
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-
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code:'sampleCode',
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8
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-
};
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-
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code_verifier:'sampleVerifierテスト',
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};
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11
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const postData=Object.entries(data).map(x=>`${encodeURIComponent(x[0])}=${encodeURIComponent(x[1])}`).join('&');
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req.open('POST',restAPIURL);
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req.setRequestHeader("Accept","application/json");
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req.setRequestHeader("cache-control","no-cache");
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req.setRequestHeader("Content-Type","application/x-www-form-urlencoded");
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req.onload = function() {
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console.log(JSON.parse(this.response));
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};
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20
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req.send(postData);
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11
21
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```
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12
22
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きょうび、fetchで送るほうが楽だとおもいます。
|
|
13
23
|
fetchの場合データはformDataで格納すればエンコードも必要ありません
|